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Otrada [13]
3 years ago
7

It's possible to build two triangles with all the same angles that are not comgruent

Mathematics
1 answer:
Juliette [100K]3 years ago
4 0

Answer:

true!

Step-by-step explanation:

they are called similar triangles!


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I need help with this
Assoli18 [71]
On a given line, (on one side) there are a total of 180°

if one line in Problem #3 is bisected by a line, with one half X and the other 120°,

do 180° (the total) minus 120° which=60°

now the hard part, that line that bisected the first line is bisecting a line that is parallel to your second line, the one with <5 and <6

this means that the big angle formed in the first one with 120° is the same angle as in the second line, leaving <5 as 120°
which means <6 is 60°, like in the top part of the problem. You're basically flipping the top line upside down, I hope it helps.
7 0
3 years ago
Which is a correct name for the angle shownv?
nirvana33 [79]
Angle CBA is the right name because it's in between C and A
3 0
3 years ago
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Solve for X<br> (5x-2)^2=17<br> please help me everyone.
beks73 [17]

Answer:

\frac{2}{5}±\frac{\sqrt{17}}{5}

Step-by-step explanation:

(5x-2)^2=17 \\ 5x-2=±\sqrt{17} \\ 5x = 2 ± \sqrt{17}   \\ x=\frac{2}{5}± \frac{\sqrt{17}}{5}

Don't mind the ±

5 0
2 years ago
Explain how to use the distributive property to find an expression that is equivalent to 20+10
nordsb [41]

Answer: 2(10+5)

Step-by-step explanation: half of 20 is 10. half of 10 is five and i put them both in parentheses. outside the parenthesis i placed 2 so it is multiplied to the inner set of numbers.

5 0
3 years ago
Read 2 more answers
The density of water is 1 gram per cubic centimeter. A more dense object will sink, and a less dense object will float. Will a m
Bogdan [553]
Ah clever. So you need two formulas.

1) Volume of the marble.

   4(pi)r^3/3
= 4(pi)(1.4)^3/3
<span>= 11.49 (approx)
</span>
2) Formula for density.
  
    D = M / V
        = 9 / 11.49
        = 0.78

0.78 < 1

Therefore the marble will float.

8 0
3 years ago
Read 2 more answers
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