Question

8. A ship leaves port at 9:00 a.m. and has a bearing of N 70° W. The ship sails

Answer 1

9514 1404 393

Answer:

• 24.6 Nm north
• 67.7 Nm west

Step-by-step explanation:

In x-y coordinates, the direction is 70° CCW from 90° (north), so is 160° from the +x axis. In 4 hours at 18 Nm/h, the ship will travel 4×18 Nm = 72 Nm.

The coordinates in the x-y plane can be found to be ...

  72(cos(160°), sin(160°)) ≈ (-67.7, 24.6)

The ship traveled 67.7 nautical miles west and 24.6 nautical miles north from the port.