8. A ship leaves port at 9:00 a.m. and has a bearing of N 70° W. The ship sails
1 answer:
9514 1404 393
Answer:
- 24.6 Nm north
- 67.7 Nm west
Step-by-step explanation:
In x-y coordinates, the direction is 70° CCW from 90° (north), so is 160° from the +x axis. In 4 hours at 18 Nm/h, the ship will travel 4×18 Nm = 72 Nm.
The coordinates in the x-y plane can be found to be ...
72(cos(160°), sin(160°)) ≈ (-67.7, 24.6)
The ship traveled 67.7 nautical miles west and 24.6 nautical miles north from the port.
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Step-by-step explanation:
y = |x - 2| - 1
Given equation is in the form of y=|x-h|+k
Where (h,k) is the vertex
h = 2 and k =-1
So (2, -1) is the vertex for the given function
To find x intercepts we plug in 0 for y
we will get two values for x because of absolute function
0 = |x-2| -1
add 1 on both sides
|x-2| =1
x-2 =1 and x-2 =-1
x= 3 and x= 1
So x intercepts are (1,0) and (3,0)
the graph is attached below
Answer:
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Step-by-step explanation:
