Answer:
We can claim with 95% confidence that the proportion of executives that prefer trucks is between 19.2% and 32.8%.
Step-by-step explanation:
We have a sample of executives, of size n=160, and the proportion that prefer trucks is 26%.
We have to calculate a 95% confidence interval for the proportion.
The sample proportion is p=0.26.
The standard error of the proportion is:
The critical z-value for a 95% confidence interval is z=1.96.
The margin of error (MOE) can be calculated as:

Then, the lower and upper bounds of the confidence interval are:

The 95% confidence interval for the population proportion is (0.192, 0.328).
We can claim with 95% confidence that the proportion of executives that prefer trucks is between 19.2% and 32.8%.
We have two fractions being divided. When we divide two fractions, we flip the second fraction and multiply
1/12 divided by 1/6 = 1/12 * 6/1
-------
From here we multiply straight across.
The numerators multiply to get 1*6 = 6
The denominators multiply to 12*1 = 12
We end up with 6/12 which reduces to 1/2 when you divide both parts by the GCF 6
<h3>Final Answer: 1/2</h3>
Answer:

Step-by-step explanation:
Recall that a <em>probability mass function</em> defined on a discrete random variable X is just a function that gives the probability that the random variable equals a certain value k
In this case we have the event
“The computer will ask for a roll to the left when a roll to the right is appropriate” with a probability of 0.003.
Then we have 2 possible events, either the computer is right or not.
Since we have 4 computers in parallel, the situation could be modeled with a binomial distribution and the probability mass function
This gives the probability that k computers are wrong at the same time.
Answer:
(-4,14)
(which you already choose)
Step-by-step explanation:
Anser: Brooo
Step-by-step explanation:
I cannot readd this