Answer:
yeet
Step-by-step explanayeettion:
10
See below for the terms, coefficients, and constants in the variable expressions
<h3>How to determine the terms, coefficients, and constants in the variable expressions?</h3>
To determine the terms, coefficients, and constants, we use the following instance:
ax + by + c
Where the variables are x and y
- Then the terms are ax, by and c
- The coefficients are a and b
- The constant is c
Using the above as guide, we have:
A) 2b + 2ac+5
- Terms: 2b, 2ac, 5
- Coefficient: 2, 2 and 5
- Constant 5
B) 34abx + 16y +1
- Terms: 34abx, 16y, 1
- Coefficient: 34ab, 16
- Constant: 1
C) st +4u + v
- Terms: st, 4u, v
- Coefficient: 4
D) 14xy + 6
- Terms: 14xy, 6
- Coefficient: 14, 6
- Constant 6
E) 14x + 12y
- Terms: 14x, 12y
- Coefficient: 14, 12
F) 3+ 6-7+a
- Terms: 3, 6, -7, a
- Coefficient: 1
- Constant: 3, 6, -7
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First we'll do two basic steps. Step 1 is to subtract 18 from both sides. After that, divide both sides by 2 to get x^2 all by itself. Let's do those two steps now
2x^2+18 = 10
2x^2+18-18 = 10-18 <<--- step 1
2x^2 = -8
(2x^2)/2 = -8/2 <<--- step 2
x^2 = -4
At this point, it should be fairly clear there are no solutions. How can we tell? By remembering that x^2 is never negative as long as x is real.
Using the rule that negative times negative is a positive value, it is impossible to square a real numbered value and get a negative result.
For example
2^2 = 2*2 = 4
8^2 = 8*8 = 64
(-10)^2 = (-10)*(-10) = 100
(-14)^2 = (-14)*(-14) = 196
No matter what value we pick, the result is positive. The only exception is that 0^2 = 0 is neither positive nor negative.
So x^2 = -4 has no real solutions. Taking the square root of both sides leads to
x^2 = -4
sqrt(x^2) = sqrt(-4)
|x| = sqrt(4)*sqrt(-1)
|x| = 2*i
x = 2i or x = -2i
which are complex non-real values
Answer: Increase in number or size, at a constantly growing rate. It is one possible result of a reinforcing feedback loop that makes a population or system grow (escalate) by increasingly higher amounts.
