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Ronch [10]
4 years ago
10

The water temperature required for a certain manufacturing process is 134°F. However, the process allows for a variation of 7°F

in the water temperature.
If x represents the water temperature, which inequality describes the situation? What is the range of water temperatures that is allowed for this process?
Mathematics
1 answer:
Y_Kistochka [10]4 years ago
3 0

Answer:

The temperature that represents a smaller value would be the one with negative eighty (or -80) degrees Fahrenheit. Although it is negative, the value of 80 does not mean it has a smaller value as to 134 degrees. It is just that the difference between the absolute values of the two show that 134 degrees Fahrenheit has a bigger value.

Step-by-step explanation:

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What is the solution to the system of equations? Use the substitution method. {y=−2x+5 {3x−4y=2 Enter your answer in the boxes.
Nataly_w [17]
1. You have the following equations:
<span>
 y=−2x+5  (i)
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 2. You must substitute the equation (i) into the equation (ii), as below:

 </span>3x−4y=2
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7 0
4 years ago
❊ Simplify :
Nataliya [291]
<h3>Need to Do :- </h3>
  • To simplify the given expression .

\red{\frak{Given}}\Bigg\{ \sf \dfrac{x - 1}{ {x}^{2} - 3x + 2} + \dfrac{x - 2}{ {x}^{2} - 5x + 6 } + \dfrac{x - 5}{ {x}^{2} - 8x + 15 }

\rule{200}4

\sf\longrightarrow \small  \dfrac{x - 1}{ {x}^{2} - 3x + 2} + \dfrac{x - 2}{ {x}^{2} - 5x + 6 } + \dfrac{x - 5}{ {x}^{2} - 8x + 15 } \\\\\\\sf\longrightarrow \small  \dfrac{ x-1}{x^2-x -2x +2} +\dfrac{ x-2}{x^2-3x-2x+6} +\dfrac{ x -5}{x^2-5x -3x + 15 } \\\\\\\sf\longrightarrow\small \dfrac{ x -1}{ x ( x - 1) -2(x-1) } +\dfrac{ x-2}{x ( x -3) -2( x -3)} +\dfrac{ x -5}{ x(x-5) -3( x -5) }  \\\\\\\sf\longrightarrow \small \dfrac{ x -1}{ ( x-2) (x-1) } +\dfrac{ x-2}{( x -2)(x-3) } +\dfrac{ x -5}{ (x-3)(x-5)  } \\\\\\\sf\longrightarrow\small \dfrac{ 1}{ x-2} +\dfrac{ 1}{ x -3} +\dfrac{1}{ x -3}   \\\\\\\sf\longrightarrow   \small  \dfrac{1}{x-2} +\dfrac{2}{x-3}  \\\\\\\sf\longrightarrow   \small \dfrac{ x-3 +2(x-2)}{ ( x -3)(x-2) }  \\\\\\\sf\longrightarrow   \small \dfrac{ x - 3 +2x -4 }{ (x-3)(x-2) }     \\\\\\\sf\longrightarrow   \underset{\blue{\sf Required \ Answer  }}{\underbrace{\boxed{\pink{\frak{  \dfrac{ 3x -7}{ ( x -2)(x-3) } }}}}}

\rule{200}4

5 0
3 years ago
Read 2 more answers
Please help i dont know if im right
stepan [7]
It says that the sum of the bases are 46 and the bases are the top and bottom, so that means that one base the top or bottom are 23 each so what do you think

5 0
4 years ago
5 ≤ - 3x- 3 ≤ 10 solve the inequality for x
kaheart [24]

Answer:

<h3>- \frac{8}{3}  \geqslant x   \geqslant - \frac{13}{3}</h3>

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • inequality
  • solving inequality
  • PEMDAS
<h3>given:</h3>

5 ≤ - 3x- 3 ≤ 10

<h3>to solve:</h3>

x

<h3>let's solve:</h3>

few notes about inequality

the direction of the inequality doesn't change if you

  • Add (or subtract) a number from both sides
  • Multiply (or divide) both sides by a positive number
  • Simplify a side

the direction of the inequality does change

if you

  • Multiply (or divide) both sides by a negative number
  • Swapping left and right hand sides

step - 1 : difine

5 \leqslant  - 3x - 3 \leqslant 10

step - 2 :  \\ add \: 3 \: in \: each \: sides

5 + 3 \leqslant  - 3x - 3 + 3 \leqslant 10 + 3

8 \leqslant  - 3x \leqslant 13

step - 3 :  \\ divide  \:  - 3\: from \: each \: sides \:  \\ and \: swap \: the \: inequalily

\therefore -  \frac{8}{3} \geqslant x \geqslant   - \frac{13}{3}

5 0
3 years ago
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