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shutvik [7]
2 years ago
13

What are the zeros of the quadratic function f(x) = 6x2 – 24x + 1?

Mathematics
1 answer:
yaroslaw [1]2 years ago
3 1

Answer:

a

Step-by-step explanation:

a

You might be interested in
According to the distributive property,6(a+b)=
olga55 [171]

Answer:

B

Step-by-step explanation:

The Distributive property says that a(b+c) = ab+ac

In my example you distribute the value on the outside to the things on the inside

In your problem, you have a six on the outside that needs to be distributed to an a and b

1) 6 multiplied by a equals 6a giving you the first part of your answer!

2) 6 multiplied by b equals 6b giving you the second part of your answer!

Dont forget that there is a + sign in between a and b, dont drop it!

Put the two values together to get 6a+6b

Let me know if you have any further questions :)

8 0
3 years ago
A rectangle-shaped garden is 4,732 square feet. The length of one side is 91 feet. What is the width of the garden?
Scilla [17]
You need to divide 4732 feet by 91 feet to get the other dimension.

4732 divided by 91 is 52 feet
6 0
3 years ago
Read 2 more answers
Three of the angles of a quadrilateral are 148 degrees 104 degrees and 36 degrees what is the size of the 4th angle
solmaris [256]
The overall angles in a quadrilateral add up to 360° so it's
360-104=256°
256-148=100°
100-36=64°
the 4th angle is 64°
6 0
3 years ago
I think it will be b but I don’t know
Naily [24]

Answer:

yeah it is b

acute and scalene

Step-by-step explanation:

scalene means none of the sides equal

and also all sides are acute angles

6 0
3 years ago
Read 2 more answers
Two boxes contained 155 lb of flour. If you take 20 lb from the first and add it to the second, the first box will contain 12/19
mestny [16]
There were originally 80lb in the first box and 75lb in the second box.

The first equation describes the original weight in each box.
x+y=155
The second equation describes the weight after the 20 pounds is removed from the first box and added to the second:
x-20=\frac{12}{19}(y+20), because 20 pounds is taken from the first box, x, and added to the second box, y; and that makes the first box equal to 12/19 of the second one.
We now have this system of equations:
\left \{ {{x+y=155} \atop {x-20=\frac{12}{19}(y+20)}} \right.
We will simplify the bottom equation first by multiplying both sides by 19 to cancel the fraction:
19(x-20)=19(\frac{12}{19})(y+20)
We use the distributive property on the left, and cancel the 19 on the right:
19*x-19*20=12(y+20)
\\19x-380=12*y+12*20
\\19x-380=12y+240
We will move the 12y to the left side of the equation by subtracting:
19x-380-12y=12y+240-12y
19x-12y-380=240
Now we will cancel the 380 by adding:
19x-12y-380+380=240+380
19x-12y=620
Now our system looks like this:
\left \{ {{x+y=155} \atop {19x-12y=620}} \right.
To eliminate a variable, we want the coefficients to be the same.  We will multiply the top equation by 19 to achieve this:
\left \{ {{19(x+y=155)} \atop {19x-12y=620}} \right.
\\
\\ \left \{ {{19x+19y=2945} \atop {19x-12y=620}} \right.
Now we will subtract the bottom equation to cancel x:
\left \{ {{19x+19y=2945} \atop {-(19x-12y=620)}} \right. 
\\
\\19y--12y=2945-620
\\19y+12y=2325
\\31y=2325
Divide both sides by 31:
31y/31=2325/31
y=75

Substituting this back into our original first equation:
x+75=155
Subtract both sides by 75:
x+75-75=155-75
x=80
4 0
2 years ago
Read 2 more answers
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