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Svetradugi [14.3K]
3 years ago
14

In circle P with m NPQ = 46 and NP=20 units find area of sector NPQ.

Mathematics
2 answers:
liraira [26]3 years ago
8 0

Answer:

160.57

Step-by-step explanation:

The formula is:

angle/360 *\pi *radius^2

Because you find the total area of the circle, but the sector only represents NPQ/360 so you have to multiply the area with that.

46/360 * \pi *20^2 = 23/180 * \pi *400

= 160.57029...

Rounded to the nearest hundredth this would be 160.57

antoniya [11.8K]3 years ago
6 0

Answer:

Round to the nearest hundredth.

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Step-by-step explanation:

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4 years ago
Find the average rate of change of f(x) = 4x² – 3 from 3 to 9.
Lina20 [59]

Answer:

44

Step-by-step explanation:

Given:

f(x) = 4x^2 - 3

Required:

Average range of change from 3 to 9

SOLUTION:

Step 1:

Find f(3) and f(9):

To find f(3), replace x with 3 in the given function

f(3) = 4(3)^2 - 3

f(3) = 4(9) - 3

f(3) = 36 - 3

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f(9) = 4(9)^2 - 3

f(9) = 4(81) - 3

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Average rate of change = \frac{f(b) - f(a)}{b - a}

Where,

a = 3, f(a) = 33

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Plug in the values into the formula for average rate of change.

= \frac{321 - 33}{9 - 3}

= \frac{288}{6}

= 44

Average rate of change = 44

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Answer:

Step-by-step explanation:

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