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3 years ago

In circle P with m NPQ = 46 and NP=20 units find area of sector NPQ.

Mathematics

2 answers:

liraira [26]3 years ago

8 0

Answer:

160.57

Step-by-step explanation:

The formula is:

$angle/360 *\pi *radius^2$

Because you find the total area of the circle, but the sector only represents NPQ/360 so you have to multiply the area with that.

$46/360 * \pi *20^2$ = $23/180 * \pi *400$

= $160.57029...$

Rounded to the nearest hundredth this would be 160.57

antoniya [11.8K]3 years ago

6 0

Answer:

Round to the nearest hundredth.

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Answer:

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Step-by-step explanation:

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3 years ago

HELP ON THIS PROBLEM!! Solve the following 0deg< x< 360deg: cos x= cos 2x

blsea [12.9K]

Answer:

$x=0^\circ,120^\circ,240^\circ,360^\circ$

Step-by-step explanation:

Use identities to set the equation up as a quadratic

$\cos x=\cos 2x;\:0^\circ \leq x \leq 360^\circ\\\\\cos x=2\cos^2 x-1\\\\0=2\cos^2 x-\cos x-1$

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$0=2u^2-u-1\\\\0=(2u+1)(u-1)$

$\displaystyle 0=2u+1\\\\0=2\cos x+1\\\\-1=2\cos x\\\\-\frac{1}{2}=\cos x\\\\120^\circ,240^\circ=x$

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Hence, $x=0^\circ,120^\circ,240^\circ,360^\circ$

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2 years ago

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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