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zmey [24]
3 years ago
13

What’s 2+2 because I need help

Mathematics
2 answers:
kvasek [131]3 years ago
7 0

Answer:

4

Step-by-step explanation:

nikklg [1K]3 years ago
3 0
4 is the answer because it’s just common sense
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The table shows numbers with the ratio x : y? Find the missing number?
prisoha [69]
X| 1 | 15 | 225 |
y| 4 |  ?  | 900 |

\dfrac{y}{x}=const.

therefore

[tex]\dfrac{4}{1}=4;\ \dfrac{900}{225}=4;\ \dfrac{?}{15}=4\to?=60[\tex]

Answer: ? = 60
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3 years ago
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The given cube has a mass of 173 grams, what is it’s density
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I think the density is 4cm.

Hope that helps you.

Step-by-step explanation:

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According to government birth statistics, the probability of a woman
lyudmila [28]

To find the probability of not having twins, we can subtract the probability of having twins from 1. This is because probabilities always add up to 1.

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D=rt What does T equal? Lol how is this possible
vampirchik [111]

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t = D/r

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4 0
3 years ago
1) UN MOVIL A SE MUEVE DESDE UN PUNTO CON VELOCIDAD CONSTANTE DE 20m/s EN EL MISMO INSTANTE A UNA DISTANCIA DE 1200m, OTRO MOVIL
alisha [4.7K]

Answer:

El móvil B necesita 60 segundos para alcanzar al móvil A y le alcanza una distancia de 2400 metros con respecto al punto de referencia.

Step-by-step explanation:

Supóngase que cada movil viaja en el mismo plano y que el móvil B se localiza inicialmente en la posición x = 0\,m, mientras que el móvil A se encuentra en la posición x = 1200\,m. Ambos móviles viajan a rapidez constante. Si el móvil B alcanza al móvil A después de cierto tiempo, el sistema de ecuaciones cinemáticas es el siguiente:

Móvil A

x_{A} = 1200\,m+\left(20\,\frac{m}{s} \right)\cdot t

Móvil B

x_{B} = \left(40\,\frac{m}{s} \right)\cdot t

Donde:

x_{A}, x_{B} - Posiciones finales de cada móvil, medidas en metros.

t - Tiempo, medido en segundos.

Si x_{A} = x_{B}, el tiempo requerido por el móvil B para alcanzar al móvil A es:

1200\,m+\left(20\,\frac{m}{s} \right)\cdot t = \left(40\,\frac{m}{s} \right)t

1200\,m = \left(20\,\frac{m}{s} \right)\cdot t

t = \frac{1200\,m}{20\,\frac{m}{s} }

t = 60\,s

El móvil B necesita 60 segundos para alcanzar al móvil A.

Ahora, la distancia se obtiene por sustitución directa en cualquiera de las ecuaciones cinemáticas:

x_{B} = \left(40\,\frac{m}{s} \right)\cdot (60\,s)

x_{B} = 2400\,m

El móvil B alcanza al móvil A a una distancia de 2400 metros con respecto al punto de referencia.

3 0
3 years ago
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