Part A
Use the binomial probability distribution formula.
p = 0.54 = probability of getting a purple marble
n = 5 = sample size
x = 2 = number of purple we want to get
The 
portion is from the nCr combination formula. The exclamation marks indicate a factorial.
Alternatively, you could use Pascal's Triangle for that portion.
<h3>Answer: 0.283831776</h3>
This decimal value is exact. Round it however you need to.
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Part B
To find the expected value, aka the mean, we multiply the sample size and probability of getting a purple marble on any single selection.
n*p = 5*0.54 = 2.7
<h3>Answer: 2.7</h3>
Answer:
Omas can buy 1 pound of walnuts.
Step-by-step explanation:
From the information given, you can say that the total cost would be equal to the result of multiplying the price per pound of granola for the number of pounds of granola plus the result of multiplying the price per pound of walnuts for the number of pounds of walnuts, which would be:
Total cost=2x+6y, where
x is the number of pounds of granola
y is the number of pounds of walnuts
Now, you can replace the values on the formula and solve for y:
12=(2*3)+6y
12=6+6y
6=6y
y=1
According to this, the answer is that Omas can buy 1 pound of walnuts.
Rational number integers because the sum using (LCD) is 13 and 17/24. Therefore, the answer can not be a whole number because it is in a fractional form. You can also put this number in a rational for which would be 312/24. This proves that it is a rational number.
Answer:
m=1/3
Step-by-step explanation:
11m- 4/3=2m+5/3
-2m. - 2m
9m -4/3=5/3
+4/3.+ 4/3
9m= 9/3
m=1/3
Answer:
Step-by-step explanation:
Hello!
The objective of this experiment is to test if a new feed + additive generates a better production of milk in cows. For this, the owner selects 13 cows and randomly separates them into two groups.
Group 1 has 8 cows that receive the new feed + additive.
Group 2 has 5 cows that were fed with the old feed.
After two weeks of feeding the animals with the different feeds, the production of milk of each group was recorded so that they can be compared.
Since you have two separate groups to wich at random two different treatments were applied and later the variable was measured, these two samples/groups are independent and the proper test to compare the population means of the milk production in both groups is a pooled t.
I hope this helps!
