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PSYCHO15rus [73]
3 years ago
14

What is (3.9 times 10 to the power of 2) times (2.3 times 20 to the power of 6)

Mathematics
1 answer:
Lady bird [3.3K]3 years ago
5 0
(3.9*10^2)(2.3*20^6)
(3.9*100)(2.3*64000000)
(390)(147200000)
57408000000 <<< is your answer
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in a right triangle the acute angles measure x+15 and 2x degrees what is the measure of the larger acute angle of the triangle
Akimi4 [234]

<span>So, x+15 + 2x = 90 </span><span>
<span>Therefore 3x = 90 - 15 = 75 </span>
<span>and so x=25. </span>

<span>So the smaller angles are x+15 = 40 degrees and 2x=50 degrees. </span>
<span>So the larger one is 50 degrees.</span></span>

5 0
3 years ago
Read 2 more answers
A quiz consists of 10 true or false questions. To pass the quiz a student must answer at least eight questions correctly.
lys-0071 [83]

Answer:

The probability of  the student will pass the quiz = .0546

Step-by-step explanation:

Given -

Total no of question = 10

If the student guesses on each question there are two outcomes true of false

the probability  of guesses  question correctly =  \frac{1}{2}

the probability  of success is (p) =  \frac{1}{2}

the probability  of guesses  question incorrectly = \frac{1}{2}

the probability  of failure is (q) = 1- p = \frac{1}{2}

If the student guesses on each question he must answered at least 8 question correctly

the probability of  the student will pass the quiz = P(X\geq8 )

= P(X = 8 ) + P(X = 9) + P(X = 10 )

= \binom{10}{8}(p)^{8}(q)^{10 - 8} + \binom{10}{9}(p)^{9}(q)^{10 - 9} + \binom{10}{10}(p)^{10}(q)^{10 - 10}

= \frac{10!}{(2!)(8!)}(\frac{1}{2})^{8}(\frac{1}{2})^{10 - 8} +\frac{10!}{(1!)(9!)} (\frac{1}{2})^{9}(\frac{1}{2})^{10 - 9} + \frac{10!}{(0!)(10!)}(\frac{1}{2})^{10}(\frac{1}{2})^{10 - 10}

= 45\times\frac{1}{2^{10}} + 10\times\frac{1}{2^{10}} + 1\times\frac{1}{2^{10}}

= \frac{56}{2^{10}}

= .0546

5 0
3 years ago
Someone please help me with the problem. it’s due tomorrow and idk what i’m doing
Hatshy [7]
For the first question:Using the distance=rate x time formula (d=rt). Your equation would be y=38x. The 38 comes from the kathryn’s speed(rate).

For the second question: because you know the distance is now 53 substitute 53 for y and solve. 53=38x. Where x represents her time. She travels the 53 miles at a rate of 38mi/h (53 divided by 38) and solve in terms of hours 1.3947or rounded to the nearest tenth 1.4 which in terms of hours is 1 hour 24 minutes.
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3 years ago
How does the value of the digit 2 in 2000 compare with the value of the digit 2 in 200
iragen [17]

Answer:

The value of 2 in 2000 is 10 times greater than the value of 2 in 200

Step-by-step explanation:

from the value of 2 in 200 to reach 2000, it takes 10 times as much because we're moving only one place (which is the thousand's digit).

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3 years ago
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Rom4ik [11]

Answer:

B

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7 0
2 years ago
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