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Crazy boy [7]
3 years ago
8

Trish is taking care of the hans family dogs. The hans leave 7 cans of dog food for the 3 days theyll be away . How many more ca

ns of dog food would trish need if she needed to feed the dogs 3 cans a day.
Mathematics
1 answer:
myrzilka [38]3 years ago
5 0

If the Hans leave for 3 days, and Tish wants to feed the dogs 3 cans each day, we can solve this problem using simple multiplication.


3 days * 3 cans / 1 day = 9 cans

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Hatshy [7]
I think the answer is C 2/3
5 0
3 years ago
Last January, the average cost of a one-night stay at a hotel was $132.52. Since then, the hotel has changed ownership, and
Nikolay [14]

Answer:

$114.32

Step-by-step explanation:

Original Price: $132.52

increased: $34.65

Loyalty Club: -$57.80

Phone Fee: $4.95

You add all of them together, except for the Loyalty Club Fee. You subtract that fee by the total.

4 0
3 years ago
Yati has a coin box containing some coins. 40% of the coins are 20-cent coins and the rest are 50-cent coins.
lana66690 [7]

The fraction that should be removed is 1/5.

<h3>How to calculate the fraction?</h3>

It should be noted that from the information, 40% of the coins are 20-cent coins and the rest are 50-cent coins. Those that are 50 cent will be:

= 100 - 40%

= 60%

The fraction that's should be removed will be:

= 2/5 - x = 1/5

x = 2/5 - 1/5

x = 1/5

The fraction that should be removed is 1/5.

Learn more about fractions on:

brainly.com/question/17220365

#SPJ1

7 0
2 years ago
I REALLY NEED HELP PLEASE!!  
disa [49]


part A)

\bf \begin{array}{ccllll}&#10;hours(x)&velocity(y)\\&#10;-----&-----\\&#10;1&6\\&#10;3&2&#10;\end{array}\\\\&#10;-------------------------------\\\\


\bf \begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%   (a,b)&#10;&({{ 1}}\quad ,&{{ 6}})\quad &#10;%   (c,d)&#10;&({{ 3}}\quad ,&{{ 2}})&#10;\end{array}&#10;\\\\\\&#10;% slope  = m&#10;slope = {{ m}}= \cfrac{rise}{run} \implies &#10;\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{2-6}{3-1}\implies \cfrac{-4}{2}\implies -2

\bf y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-6=-2(x-1)\\&#10;\left. \qquad   \right. \uparrow\\&#10;\textit{point-slope form}&#10;\\\\\\&#10;y-6=-2x+2\implies y=-2x+2+6\implies \boxed{y=-2x+8}

part B)

well, we know y = -2x+8.... so.. what's the runner's velocity after 5hours? well, x = 5, thus y = -2(5) +8 ---> y = -2

to graph it, well, is a LINEar equation, meaning the graph is a LINE, and to graph a line, all you need is two points, and by now, you have more than two.. so graph it away.
7 0
3 years ago
Can I please have help?
jok3333 [9.3K]

Answer:

(-3, 3) and (8, -8)

Step-by-step explanation:

having the rule (x + 3, y – 5) and an input point (x,y) you just plu th iput point into the rule and you will get the output point.

With an input point (-6,8) you plug -6 in for x and 8 in for y into the rule.  

(x + 3, y – 5)

(-6 + 3, 8 - 5)

(-3, 3)

Now we do the same for (5, -3) as the input

(x + 3, y – 5)

(5 + 3, -3 - 5)

(8, -8)

4 0
3 years ago
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