All categories

2 years ago

Find the values of the vertex and Axis of symmetry.

Mathematics

1 answer:

Thepotemich [5.8K]2 years ago

6 0

Answer:

Step-by-step explanation:

The vertex is at the turning point. According to the graph, that point is (-2,3).

The axis of symmetry passes through the vertex: x = -2

You might be interested in

In which branch of statistics would a researcher acquire twenty-five 2000 Toyota Celicas, drive them until they had a major mech

AURORKA [14]

Answer:

The answer is "descriptive statistics".

Step-by-step explanation:

Descriptive statistics are short descriptive factors that add up a production set, that can be either a reflection of a whole or a sample population. It is broken down into cumulative frequency measurements and variance measurements. The study uses descriptive statistics to explain the profile of the respondents. People give simple summaries about the sample as well as the actions.

6 0

2 years ago

Solve the equation: 13W - 2(4W + 1) = W - 58 *

Sergio [31]

Answer:

W = - 14

Step-by-step explanation:

13W - 2(4W + 1) = W - 58

13W - 8W - 2 = W - 58

13W - 8W - W = 2 - 58

4W = - 56

W = - 56 : 4

W = - 14

6 0

2 years ago

Read 2 more answers

What is the answer using the majic method of factoring?

NeX [460]

2x² - 15x + 7
(2x - 1)(2x-14)

(2x - 1)(x - 7) x= 1/2 or 7

7 0

3 years ago

What is the fourth term in the binomial expansion (a+b)^6)

Dafna11 [192]

Answer:

$20a^3b^3$

Step-by-step explanation:

<u>Binomial Series</u>

$(a+b)^n=a^n+\dfrac{n!}{1!(n-1)!}a^{n-1}b+\dfrac{n!}{2!(n-2)!}a^{n-2}b^2+...+\dfrac{n!}{r!(n-r)!}a^{n-r}b^r+...+b^n$

<u>Factorial</u> is denoted by an exclamation mark "!" placed after the number. It means to multiply all whole numbers from the given number down to 1.

Example: 4! = 4 × 3 × 2 × 1

Therefore, the fourth term in the binomial expansion (a + b)⁶ is:

$\implies \dfrac{n!}{3!(n-3)!}a^{n-3}b^3$

$\implies \dfrac{6!}{3!(6-3)!}a^{6-3}b^3$

$\implies \dfrac{6!}{3!3!}a^{3}b^3$

$\implies \left(\dfrac{6 \times 5 \times 4 \times \diagup\!\!\!\!3 \times \diagup\!\!\!\!2 \times \diagup\!\!\!\!1}{3 \times 2 \times 1 \times \diagup\!\!\!\!3 \times \diagup\!\!\!\!2 \times \diagup\!\!\!\!1}\right)a^{3}b^3$

$\implies \left(\dfrac{120}{6}\right)a^{3}b^3$

$\implies 20a^3b^3$

7 0

1 year ago

16 17 18 number plz answer righg

marta [7]

What does this even mean

7 0

2 years ago