Answer:
As you go down group 1, the number of electron shells increases – lithium has two, sodium has three, and so forth. The attraction from the positive nucleus to the negative electron is less. This makes it easier to remove the electron and makes the atom more reactive.
Answer is: metal is lead with density of 11,4 g/cm³.
Text that missing: a sample of an unkwown metal has a mass of 35,4 g and a volume of 3,11 cm³.
m(metal) = 35,4 g.
V(metal) = 3,11 cm³.
d(metal) = m(metal) ÷ V(metal)
d(metal) = 35,4÷ g ÷ 3,11 cm³
d(metal) = 11,4 g/cm³.
The element that would have 4 electrons in its outer p orbital, or p subshell would be Oxygen. Oxygen's electronic configuration would suggest that there are 4 electrons in its p sub shell.
O : 1s^2 2s^2 2p^4.
Answer:
The answer is C)
Explanation:
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Answer:
how can I solve this ?4Al+3O2 produce 2Al2O3 find a) oxygen atoms needed to react with 5.4 g of aluminium b) grams of oxygen needed to react with 0.6 mol of aluminium?
(A) n=m/M,
n(Al)=5.4/27=0.2 moles
n(O2)=n(Al)*3/4=0.2*3/4=0.15 moles
Number of oxygen atoms= n(O2)*Avogadro's number
=0.15*6.02*10^23=9.03*10^22 oxgyen atoms
(B)
n=m/M
n(Al)=0.6/27=0.02222 moles
n(O2)=n(Al)*3/4=0.016666 moles
m=n*M
m(O2)=0.0166666*32=0.53333 grams
