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3 years ago

9. What is 999 x 4 =

Mathematics

2 answers:

zimovet [89]3 years ago

7 0

999 x 4 equals 3,996

Veronika [31]3 years ago

3 0

999*4=3996 if this helps any

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Evaluate the line integral, where c is the given curve. (x + 9y) dx + x2 dy, c c consists of line segments from (0, 0) to (9, 1)

viktelen [127]

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=\int_C\langle x+9y,x^2\rangle\cdot\underbrace{\langle\mathrm dx,\mathrm dy\rangle}_{\mathrm d\mathbf r}$

The first line segment can be parameterized by $\mathbf r_1(t)=\langle0,0\rangle(1-t)+\langle9,1\rangle t=\langle9t,t\rangle$ with $0\le t\le1$ . Denote this first segment by $C_1$ . Then

$\displaystyle\int_{C_1}\langle x+9y,x^2\rangle\cdot\mathbf dr_1=\int_{t=0}^{t=1}\langle9t+9t,81t^2\rangle\cdot\langle9,1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(162t+81t^2)\,\mathrm dt$
$=108$

The second line segment ( $C_2$ ) can be described by $\mathbf r_2(t)=\langle9,1\rangle(1-t)+\langle10,0\rangle t=\langle9+t,1-t\rangle$ , again with $0\le t\le1$ . Then

$\displaystyle\int_{C_2}\langle x+9y,x^2\rangle\cdot\mathrm d\mathbf r_2=\int_{t=0}^{t=1}\langle9+t+9-9t,(9+t)^2\rangle\cdot\langle1,-1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(18-8t-(9+t)^2)\,\mathrm dt$
$=-\dfrac{229}3$

Finally,

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=108-\dfrac{229}3=\dfrac{95}3$

5 0

3 years ago

What is the equation of the line written in general form?

Irina18 [472]

I think its b or c but my best guess would be b

7 0

3 years ago

What is 2 X (6+ 2 + 8) -4

VladimirAG [237]

Answer:

The correct answer is 32x - 4

Step-by-step explanation:

1) Simplify 6 + 2 to 8.

$2x(8 + 8) - 4$

2) Simplify 8 + 8 to 16.

$2x \times 16 - 4$

3) Simplify 2x × 16 to 32x.

$32x - 4$

Therefor, the answer is 32x - 4.

4 0

2 years ago

Show another way to write 100 more than 623

____ [38]

There are many ways, but here is one:

x = 100

Since ‘x’ is 100 and we want 100 more, we just need to add ‘x’ to 623

Answer: x + 623 (Make sure you define your ‘x’ value)

4 0

2 years ago

Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Anit [1.1K]

Well the area of a trapezoid is defined by the following formula:
A = $\frac{1}{2}(b_{1} + b_{2})h$ where b₁ and b₂ are the bases of the trapezoid and h is the height of the trapezoid.

Let's plug in what we know into this formula:
h = 7 the perpendicular distance between the two bases
b₁ = 15 the shorter parallel side
b₂ = 25 the longer parallel side made up of 4 + 15 + 6
so, A = $\frac{1}{2} (15+25)(7)=140$

This is in square units of measure of course, so 140 in²

8 0

3 years ago