1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Rainbow [258]
3 years ago
14

Tell whether each equation has one, zero, or infinitely many solutions.5(x - 3) +6= 5x - 9​

Mathematics
1 answer:
ollegr [7]3 years ago
3 0

5(x - 3) +6 = 5x - 9​ has infinitely many solutions

<h3><u>Solution:</u></h3>

Given equation is 5(x - 3) +6 = 5x - 9​

We have to find whether the given equation has one, zero, or infinitely many solutions

Let us solve the given equation

5(x - 3) + 6 = 5x - 9​

Let us use BODMAS rule to solve the given equation

According to Bodmas rule, if an expression contains brackets ((), {}, []) we have to first solve or simplify the bracket followed by of (powers and roots etc.), then division, multiplication, addition and subtraction from left to right

So let us first solve for brackets in given equation

5x - 15 + 6 = 5x - 9

5x - 9 = 5x - 9

0 = 0

Since the statement is true, there are infinitely many solutions

You might be interested in
Suppose that y varies inversely as x and that y=8 when x=3. Calculate the value of y when x= 10.
Svetach [21]

\bf \qquad \qquad \textit{inverse proportional variation} \\\\ \textit{\underline{y} varies inversely with \underline{x}} ~\hspace{6em} \stackrel{\textit{constant of variation}}{y=\cfrac{\stackrel{\downarrow }{k}}{x}~\hfill } \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \textit{we know that } \begin{cases} y = 8\\ x = 3 \end{cases}\implies 8=\cfrac{k}{3}\implies 24=k~\hfill \boxed{y = \cfrac{24}{x}} \\\\\\ \textit{when x = 10, what is \underline{y}?}\qquad \qquad y = \cfrac{24}{10}\implies y = \cfrac{12}{5}

3 0
3 years ago
1 8/9 divided by 1/6
kkurt [141]

11 1/3 is the answer in fraction form but i decimal form it is 11.3 and the exact form is 34/3

4 0
3 years ago
Read 2 more answers
10 ft
Lelu [443]

Answer:

P = 40.56 ft

Step-by-step explanation:

The figure is composed of a rectangle and half circle

The perimeter of the figure = the length of the borders round the figure

= W + 2L + ½(perimeter of full circle)

W = 8 ft

L = 10 ft

½(perimeter of circle) = ½(πd) = ½(3.14*8)

= 12.56 ft

Plug in the values

Perimeter of the figure = 8 + 2(10) + 12.56

= 8 + 20 + 12.56

= 40.56 ft

3 0
3 years ago
Describe the solution to the inequality m&gt; -1
irga5000 [103]
1>-1 behxjxjsjdjdjsssss
8 0
3 years ago
PLEASE HELP with these math questions (Please don't answer if you don't know all of them)
Leona [35]
Sqrt (53) = 10 * sqrt (0.53)

0.53 = 64/121
sqrt (0.53) = sqrt (64)/ sqrt (121) = 8/11 = 0.7273
Therefore sqrt (53) = 10 * 0.7273 = 7.27

sqrt (108) = 10 * sqrt (1.08)
sqrt (1.08) = sqrt (676/625) = 26/25 = 1.04
Therefore sqrt (108) = 10 * 1.04 = 10.4

sqrt (128) = 10 * sqrt (1.28)
sqrt (1.28) = sqrt (289/225) = 17/15 = 1.133
Therefore sqrt (108) = 10 * 1.133 = 11.33

5 0
3 years ago
Other questions:
  • Which ordered pair describes the location of the red point?
    10·2 answers
  • Solve the equation. Determine whether the equation has one solution, no solution, or
    7·2 answers
  • What is two thirds times negative one
    15·2 answers
  • Which Quadratic equation is equivalent to (x-4)^2-(x-4)-6=0
    13·2 answers
  • What is (2/5 +1/5) - 3/10 ?
    5·2 answers
  • A wooden flooring strip is 20 1/2 inches long. If you cut off 4 3/4 inches from one end what will be the new length of the strip
    9·1 answer
  • The net of a cube is shown. What is the surface area of the cube?. Need help asap ill mark brainlest ​
    13·1 answer
  • A candy bar box is in the shape of a triangular prism. The volume of the box is 3,240 cubic centimeters. A triangular prism is s
    12·1 answer
  • 2
    7·1 answer
  • Find the coordinates of the other endpoint of the segment, given its midpoint and one endpoint. (Hint: Let (×,y) be the unknown
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!