When the oxyhemoglobin curve shifts during exercise what is the result?
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If you were to compute this, Angle C should be equal to 100°.
In a triangle, all angles sum up to 180°.
In triangle ABC, where the m∠A =30° and m∠50°:
m∠A + m∠B + m∠C = 180°
30° + 50 + m∠C = 180°
80° + m∠C = 180°
m∠C = 180° - 80°
m∠C = 100°
The triangle should look like the picture attached.
In a triangle, all angles sum up to 180°.
In triangle ABC, where the m∠A =30° and m∠50°:
m∠A + m∠B + m∠C = 180°
30° + 50 + m∠C = 180°
80° + m∠C = 180°
m∠C = 180° - 80°
m∠C = 100°
The triangle should look like the picture attached.
You should mix 4µl of DNA sample and complete it with 96µl (100-4) of water.
You can figure this out by using C1.V1 = C2.V2
C1 = 250 <span>ng/μl (Sample Concentration)
</span>V1 = ? (the necessary volume to take from the DNA sample)
C2 = 10 <span>ng/μl (PCR concentration)
</span>V2 = 100 µl (total volume)
V1 =
= 
= 4µl
For the water: 100µl (total volume) = 4µl + Water
Water volume = 96µl
You can figure this out by using C1.V1 = C2.V2
C1 = 250 <span>ng/μl (Sample Concentration)
</span>V1 = ? (the necessary volume to take from the DNA sample)
C2 = 10 <span>ng/μl (PCR concentration)
</span>V2 = 100 µl (total volume)
V1 =
For the water: 100µl (total volume) = 4µl + Water
Water volume = 96µl