Given:
Degree of a polynomial is 7.
To find:
The possible combination of root types for a 7th degree polynomial.
Solution:
We know that, by complex conjugate root theorem, is a complex number is a root of a polynomial, then its conjugate is also the root of that polynomial, it means number of complex roots always an even number.
Similarly,
Irrational roots are also occurs in pairs. If is a root of polynomial, then its is also the root of that polynomial, it means number of irrational roots always an even number.
In options A, B and C either complex or irrational roots are odd, which is not true.
Therefore, the correct option is D.
On the y-axis, the graph crosses 0 because proportional relationships start at the origin, or (0,0). The line will be straight because a proportional relationship has a constant, meaning it will have a constant rate of change, therefore, it is linear.
Answer: x=1
Solution: 2x-2x + 3 = 5x-2x
3=3x
3/3=3x/3
x=1
Answer:
False. All triangles must have a total of 180°. 60° + 60° + 70° = 190°.
41 bc it is prime and the ones is 3 less than the 10s