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Lyrx [107]
3 years ago
6

A drawer contains 3 red paper clips 5 green paper clips and 4 blue paperclips one paper clip is taken from the drawer then repla

ced another paper clip is taken from the drawer what is the probability that the first paper clip is red and the second paper clip is blue?
Mathematics
2 answers:
Neporo4naja [7]3 years ago
6 0

Answer:

3/12 for red

4/12 for blue

Step-by-step explanation:

3 is red

5 is green

4 is blue

3 + 5 + 4 is 12 so it is out of 12 altogether

3/12 for red

4/12 for blue

kotegsom [21]3 years ago
5 0

Answer:

1/12

Step-by-step explanation:

To find the probability of the event occuring, we need to find the probabilites of taking a red paperclip and taking a blue paperclip and then multiply them together.

Red paperclip:

3/12 = 1/4

Blue paperclip:

4/12 = 1/3

Probability of event:

3/12 x 4/12 = 12/144 = 1/12

1/4 x 1/3 = 1/12

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Which of the following is equal to 5 1/3
Andrews [41]

Answer:

C

Step-by-step explanation:

Using the rule of radicals/ exponents

a^{\frac{m}{n} } ⇔ \sqrt[n]{a^{m} }

Given

5^{\frac{1}{3} } = \sqrt[3]{5} → C

7 0
3 years ago
3n-5=8(6+5n) addition property of equality
blagie [28]

Answer:

exact form:  n=-53/37

Step-by-step explanation:

isolate the variable by dividing each side by factors that don't contain the variable.

4 0
3 years ago
The long jump distances of four students are listed in the table below. How much farther
Papessa [141]
I can’t answer this with out the distance they jumped.
7 0
4 years ago
Picture Added Triangles <br> AA <br> SSS<br> SAS<br> Not Similar
rewona [7]

Answer:

Not Similer

Step-by-step explanation:

we can use the process of elimination, first AA isn't it because the corresponding angles arn't equal, next SSS itsn't it because we don't know the side lengths, and lastly SAS isn't it because we still don't know the side lengths.

5 0
3 years ago
The National Cancer Institute estimates that 3.65% of women in their 60s get breast cancer. A mammogram can typically identify c
masha68 [24]

Answer:

39.17% probability that a woman in her 60s who has a positive test actually has breast cancer

Step-by-step explanation:

Bayes Theorem:

Two events, A and B.

P(B|A) = \frac{P(B)*P(A|B)}{P(A)}

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

In this question:

Event A: Positive test.

Event B: Having breast cancer.

3.65% of women in their 60s get breast cancer

This means that P(B) = 0.0365

A mammogram can typically identify correctly 85% of cancer cases

This means that P(A|B) = 0.85

Probability of a positive test.

85% of 3.65% and 100-95 = 5% of 100-3.65 = 96.35%. So

P(A) = 0.85*0.0365 + 0.05*0.9635 = 0.0792

What is the probability that a woman in her 60s who has a positive test actually has breast cancer?

P(B|A) = \frac{0.0365*0.85}{0.0792} = 0.3917

39.17% probability that a woman in her 60s who has a positive test actually has breast cancer

7 0
3 years ago
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