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zvonat [6]
3 years ago
13

Can you please help me

Mathematics
1 answer:
yarga [219]3 years ago
8 0
With pleasure. broooooo
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Graph a line whose x-intercept is 9 and y-intercept is 7​
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Didn’t draw the other lines cuz I’m lazy lol but this the right answer

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Can anyone help me solve this Algebra 2 Problem, i literally cant figure it out
Andrews [41]

Answer:

Zeros : 1 , -1, 3

Degree : 4

End Behaviour : At x-> ∞ f(x) -> ∞ and x->-∞ f(x) -> ∞

Y - intercept : -3

Extra Points: (0,-3), (2,-3)

Step-by-step explanation:

f(x) = 0 to find the zeros

Therefore (x+1)(x-1)^{2} (x-3) = 0

Clearly x = -1,1,3

Here 1 is a repeating root as it is (x-1)²

Degree is highest power of x in f(x)

Clearly it is x*x²*x = x⁴ is the maximum power of x

Thus degree is 4

Looking at end behavior we substitute x->∞ and x-> -∞

Clearly f(x)>0 as all terms are positive and f(x)->∞

Similarly when x->-∞

f(x)>0 as 2 terms are -ve and their product is positive thus f(x)-> ∞

Y-Intercept is f(0)

f(0) = (0+1)(0-1)²(0-3) = 1*1*-3 = -3

Thus Y-Intercept is -3

Substitute x = 0 , 2 for extra points

Thus f(0) = -3

and f(2) = -3

Thus points on the graph (0,-3), (0,2)

We can use all this information to draw a graph remember that 1 is a repeating root so that will be a point of minima. The graph is a parabola that passes through x-axis at x = -1, 3.

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Step-by-step explanation:

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If a puppet requires 3/4 yard of material, how many puppets can be made from 9 yards of material?
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3 years ago
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