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zvonat [6]
3 years ago
13

Can you please help me

Mathematics
1 answer:
yarga [219]3 years ago
8 0
With pleasure. broooooo
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A bus driver applies a force of 55.0 N to the steering wheel which in turn applies 132 N of force on the steering column What is
sertanlavr [38]

Answer:

2.4

Step-by-step explanation:

132/55=2.4

MA=output force/input force.

5 0
2 years ago
Determine the slope of the line.
Akimi4 [234]

Answer:

2

Step-by-step explanation:

→ Find 2 points from the line

( 0 , 6 ) and ( - 3 , 0 )

→ Find the change in y coordinates

0 - 6 = -6

→ Find the change in x coordinates

-3 - 0 = -3

→ Divide the 2 results

-6 ÷ -3 = 2

7 0
2 years ago
Guys I really need help on this please
madreJ [45]

Answer:

The answer is 26.2.

Step-by-step explanation:

To get the answer we take the miles done in the race, in this case 18.34 and he is 70% done the race. To find out how much total miles are in the race, we  convert 70% into a decimal which is 0.70.  then we have 18.34 and 0.70 to multiply. 18.34 x 0.70=26.2 Which is your answer.

Hope this helps!

3 0
3 years ago
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Yuliya22 [10]

Answer:  I need help with this problem toooo. Does anyone know how to do it?

Step-by-step explanation:

6 0
2 years ago
You roll a pair of fair dice until you roll “doubles” (i.e., both dice are the same). what is the expected number, e[n], of roll
bonufazy [111]

We need to define our outcomes and events.

 

Finding the probability<span> of each event occurring separately, and then multiplying the probabilities is the step to <span>finding  the probability</span> of two independent events that occur in sequence.

</span>

<span>
To solve this problem, we take note of this:</span>

 

The roll of the two dice are denoted by the pair

(I, j) ∈ S={ (1, 1),(1, 2),..., (6,6) }

Each pair is an outcome. There are 36 pairs and each has probability 1/36. The event “doubles” is { (1, 1),(2, 2)(6, 6) } has probability p= 6/36 = 1/6. If we define ”doubles” as a successful roll, the number of rolls N until we observe doubles is a geometric (p) random variable and has expected value E[N] = 1/p = 6.

3 0
3 years ago
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