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77julia77 [94]
4 years ago
6

Mathematical

Mathematics
1 answer:
ludmilkaskok [199]4 years ago
4 0

Answer:

Sometimes true

Step-by-step explanation:

Examples:

Denominators are 2 & 3

LCM is 6 (2×3 = 6)

True here

Denominators are 2 & 6

LCM is 6 (2×6 = 12)

Not true here

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If x = 1 is a common root of ax² +ax + 2 = 0 and x² + x + b = 0 , then ab =
vodka [1.7K]

Answer:

ab = 2

Step-by-step explanation:

Given equations

ax² +ax + 2 = 0

x² + x + b = 0

root of both the equation

x= 1

then we can plug in x = 1 in both the equation

ax² +ax + 2 = 0                        x² + x + b = 0

a*1² +a*1 + 2 = 0                        1² + 1 + b = 0

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Thus,

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b = -2

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ab = 2

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