Answer:
V(car) = V(truck) at t = Dt/2
acceleration = v(car) = D/t^2
Explanation:
acceleration = v(car) = D/t^2
Since the average velocities must be the same, the car's final velocity must be twice the trunk velocity assuming the car start with zero velocity, since acceleration remain the same throughout the journey velocities at half-time point must be equal.
Refer to the diagram shown below.
Let T = the tension in each wire.
For equilibrium,
2T cos(50°) = 150 N
1.2856T = 150
T = 116.677 N ≈ 117 N
Answer: 117 N
After my ythorough researching, the orbital velocity of the Earth compare to the Mercury is relative to each other. In addition, Mercury orbits the Sun and it is within the Earth's orbit as its lesser or inferior. The correct answer to the following given statement above is relative to each other.
Given that,
bug speed, v= 0.85 m/s
time, t =42 s
Final position of bug on meter stick was 27 cm
Starting position of bug on meter stick = ?
Since we know that,
s = vt
s= 0.85*42 = 35.7 cm
this is the distance covered by bug in the given time and velocity.
since the bug is moving in negative direction, starting point will be:
27.0 cm+ 35.7 cm = 62.7 cm
The bugs starting position on meter stick was 62.7 cm.
Answer:
the impact on the water varies from different heights, therefore the mass stays the same, yet the force on the water increases from a higher height. A taller height will produce a bigger splash!
Explanation:
