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Brilliant_brown [7]
4 years ago
10

Derive an expression for the acceleration of the car. Express your answer in terms of D and vt Determine the time at which the s

peed of the car is equal to the speed vt of the truck. Express your answer in terms of tD. Justify your answer.
Physics
1 answer:
Bezzdna [24]4 years ago
3 0

Answer:

V(car) = V(truck) at t = Dt/2

acceleration = v(car) = D/t^2

Explanation:

acceleration = v(car) = D/t^2

Since the average velocities must be the same, the car's final velocity must be twice the trunk velocity assuming the car start with zero velocity, since acceleration remain the same throughout the journey velocities at half-time point must be equal.

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When 15 newtons of force is applied to the 0.5 kg book, the friction keeps the book from sliding down the wall. What is the mini
valkas [14]

Answer:

15 N and 3.061

Explanation:

From the question,

The minimum force of friction to keep the book from sliding = 15 N.

using

F = mgμ................. Equation 1

Where F = Frictional Force, m = mass of the book, g = acceleration due to gravity, μ = coefficient of friction.

make μ the subject of the equation

μ = F/mg............... Equation 2

Given: F = 15 N, m = 0.5 kg, g = 9.8 m/s²

Substitute into equation 2

μ = 15(0.5×9.8)

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μ = 3.061

Hence the coefficient of friction to keep the book from sliding = 3.061

4 0
4 years ago
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Answer:

He's 3 miles west of school.

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He went 5 miles up and 5 miles down which means that he really didn't go up or down.  In between that, he went 3 miles west so if the 5 milers don't count, this puts him at 3 miles west of school.

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What type of telescope did Galileo use to observe Jupiter?
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A Carnot engine absorbs 1, 3 MJ of heat at 427 degree C and exhausts heat to a reservoir at 90 degree C. How much work does it d
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3 years ago
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