Answer:
Can you help me with this pls
Answer:
15 N and 3.061
Explanation:
From the question,
The minimum force of friction to keep the book from sliding = 15 N.
using
F = mgμ................. Equation 1
Where F = Frictional Force, m = mass of the book, g = acceleration due to gravity, μ = coefficient of friction.
make μ the subject of the equation
μ = F/mg............... Equation 2
Given: F = 15 N, m = 0.5 kg, g = 9.8 m/s²
Substitute into equation 2
μ = 15(0.5×9.8)
μ = 15/4.9
μ = 3.061
Hence the coefficient of friction to keep the book from sliding = 3.061
Answer:
He's 3 miles west of school.
Explanation:
He went 5 miles up and 5 miles down which means that he really didn't go up or down. In between that, he went 3 miles west so if the 5 milers don't count, this puts him at 3 miles west of school.
<span>Carnot cycle efficiency = work done/heat supplied = (Th - Tc)/Th
where, Th is temperature of hot reservoir and Tc is temperature of cold reservoir.
we have given the values as Heat supplied = 1.3 MJ or 1300 KJ, Th = 427 degree C and Tc = 90 degree C.
converting degree Celsius to kelvin temperatures, Th = 427 + 273 = 700 K
Tc = 90 +273 = 363
solving equations, (700 - 363)/700 = work done / 1300
work done = 625.86 KJ i.e. 0.626 MJ work is done .</span>