Answer:
10 m/s
Explanation:
= Mass of arrow = 1 kg
= Mass of apple = 2 kg
= Initial Velocity of arrow = 30 m/s
= Initial Velocity of apple = 0 m/s
= Velocity of combined mass
For elastic collision
![m_1u_1 + m_2u_2 =(m_1 + m_2)v\\\Rightarrow v=\frac{m_1u_1 + m_2u_2}{m_1 + m_2}\\\Rightarrow v=\frac{1\times 30 + 2\times 0}{1 + 2}\\\Rightarrow v=10\ m/s](https://tex.z-dn.net/?f=m_1u_1%20%2B%20m_2u_2%20%3D%28m_1%20%2B%20m_2%29v%5C%5C%5CRightarrow%20v%3D%5Cfrac%7Bm_1u_1%20%2B%20m_2u_2%7D%7Bm_1%20%2B%20m_2%7D%5C%5C%5CRightarrow%20%20v%3D%5Cfrac%7B1%5Ctimes%2030%20%2B%202%5Ctimes%200%7D%7B1%20%2B%202%7D%5C%5C%5CRightarrow%20v%3D10%5C%20m%2Fs)
Final velocity of apple and arrow after collision is 10 m/s
The answer is 0 because of the velocity “u” doesn’t A
Answer:
P_h= P_0 e^{\frac {-mgh}{kT}}
Explanation:
Because it also can be apart of the milky way galaxy
Answer: 1600 km from the surface
Explanation:
![E = \frac{GM}{R^{2} }\\g1 = \frac{GM}{R1^{2} } \\R1 = 6400 km\\g2 = 0.64g1\\\frac{g1}{g2} = \frac{\frac{GM}{R1^{2} } }{\frac{GM}{R2^{2} } } \\\frac{g1}{0.64g1} = \frac{R2^{2}}{R1^{2} }\\\frac{1}{0.64} = \frac{R2^{2}}{6400^{2} }\\\\\frac{1}{0.8} = \frac{R2}{6400}\\\\R2 = \frac{6400}{0.8}\\R2 = 8000 km\\](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7BGM%7D%7BR%5E%7B2%7D%20%7D%5C%5Cg1%20%3D%20%5Cfrac%7BGM%7D%7BR1%5E%7B2%7D%20%7D%20%5C%5CR1%20%3D%206400%20km%5C%5Cg2%20%3D%200.64g1%5C%5C%5Cfrac%7Bg1%7D%7Bg2%7D%20%3D%20%5Cfrac%7B%5Cfrac%7BGM%7D%7BR1%5E%7B2%7D%20%7D%20%7D%7B%5Cfrac%7BGM%7D%7BR2%5E%7B2%7D%20%7D%20%7D%20%5C%5C%5Cfrac%7Bg1%7D%7B0.64g1%7D%20%3D%20%5Cfrac%7BR2%5E%7B2%7D%7D%7BR1%5E%7B2%7D%20%7D%5C%5C%5Cfrac%7B1%7D%7B0.64%7D%20%3D%20%5Cfrac%7BR2%5E%7B2%7D%7D%7B6400%5E%7B2%7D%20%7D%5C%5C%5C%5C%5Cfrac%7B1%7D%7B0.8%7D%20%3D%20%5Cfrac%7BR2%7D%7B6400%7D%5C%5C%5C%5CR2%20%3D%20%5Cfrac%7B6400%7D%7B0.8%7D%5C%5CR2%20%3D%208000%20km%5C%5C)
Therefore, 8000 km - 6400 km = 1600 km from the surface