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sergey [27]
3 years ago
13

An object is suspended from the ceiling with two wires that make an angle of 40° with the ceiling. The weight of the body is 150

N. What is the tension in each wire?
41.6 newtons
82.3 newtons
150 newtons
117 newtons

Physics
1 answer:
MaRussiya [10]3 years ago
5 0
Refer to the diagram shown below.

Let T =  the tension in each wire.
For equilibrium,
2T cos(50°) = 150 N
1.2856T = 150
T = 116.677 N ≈ 117 N

Answer: 117 N

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while performing a sonogram, to minimize risk to the fetus, which imaging mode trade off would be most appiclable.
Alexus [3.1K]

Answer: Use M-mode instead of pulse-wave Doppler to measure the fetal heart rate.

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4 years ago
In Ampere's law, ∮????⃗∙????????⃗=????0???? the direction of the integration around the path:
kupik [55]

Answer:

C) must be such as to follow the magnetic field lines.

Explanation:

Ampere's circuital law helps us to calculate magnetic field due to a current carrying conductor. Magnetic field due to a current forms closed loop around the current . If a  net current of value I creates a magnetic field B around it , the line integral of magnetic field around a closed path becomes equal to μ₀ times the net current . It is Ampere's circuital law . There may be more than one current passing through the area enclosed by closed curve . In that case we will take net current by adding or subtracting them according to their direction.

It is expressed as follows

∫ B.dl = μ₀ I . Here integration is carried over closed path . It may not be circular in shape. The limit of this integration must follow magnetic field lines.

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4 years ago
A small sandbag is dropped from rest from a hovering hot-air balloon. (assume the positive direction is upward.) (a) after 1.5 s
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solution:

We know v0 = 0, a = 9.8, t = 4.0. We need to solve for v

so,

we use the equation:

v = v0 + at

v = 0 + 9.8*4.0

v = 39.2 m/s

Now we just need to solve for d, so we use the equation:

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3 0
3 years ago
A series AC circuit contains a resistor, an inductor of 220 mH, a capacitor of 5.50 μF, and a generator with ΔVmax = 240 V opera
ki77a [65]

Answer:

Xl=wL=69.11503383 ohm

Xc=\frac{-1}{wC}= -578.7452476 ohm

Z=\frac{240}{140*10^-3}=1.714285714 kilo-ohm

R=2.223915928 kilo-ohm

\alpha = -12.90698798 centigrades

Explanation:

L=220*10^-3

C=5.50*10^-6

Vmax=240V

Imax=140*10^-3

w=2\pi f=2\pi *50=314.1592654

The capacitive reactance is given by:

Xc=\frac{-1}{wC}=-578.7452476 ohm

Now,  The inductive reactance is given by:

Xl=wL=69.11503383 ohm

By the ohm´s law, the electrical impedance is:

V=IZ

So

Z=\frac{V}{I}

Z=\frac{240}{140*10^-3}=1.714285714 kilo-ohm

The total impedance is:

Z=R+jX\\\\ (*)

Where X is the total reactance given by:

X=Xl+Xc=69.11503383-578.7452476=-509.6302138

Let´s calculate the real part of Z using (*):

R=1714.285714+509.6302138

R=2.223915928 kilo-ohm

Finally the angle between the current and the voltage is equal to the impedance angle:

\alpha=arctan(\frac{-509.6302138}{2223.915928})

\alpha =-12.90698798 centigrades

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Answer:

C. oversaturated

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