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EleoNora [17]
3 years ago
11

Can you help me to solve this​

Mathematics
2 answers:
bixtya [17]3 years ago
6 0
Answer: 4a-2/2a+1
Explanation: first factor out the expression. Second cancel out

Ber [7]3 years ago
3 0

Answer:

\frac{4a-2}{2a+1}

Step-by-step explanation:

Factorise the numerator and denominator

8a² - 2 ← factor out 2 from each term

= 2(4a² - 1) ← 4a² - 1 is a difference of squares

= 2(2a - 1)(2a + 1)

4a² + 4a + 1 ← is a perfect square

= (2a + 1)²

Thus

\frac{8a^2-2}{4a^2+4a+1}

= \frac{2(2a-1)(2a+1)}{(2a+1)(2a+1)} ← cancel (2a + 1) on numerator/ denominator

= \frac{2(2a-1)}{2a+1}

= \frac{4a-2}{2a+1}

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