Answer:
Which of the following statements about the First Amendment’s religion clause are true?
Check all of the boxes that apply.Which of the following statements about the First Amendment’s religion clause are true?
Check all of the boxes that apply.Which of the following statements about the First Amendment’s religion clause are true?
Check all of the boxes that apply.
Step-by-step explanation:
Which of the following statements about the First Amendment’s religion clause are true?
Check all of the boxes that apply.Which of the following statements about the First Amendment’s religion clause are true?
Check all of the boxes that apply.Which of the following statements about the First Amendment’s religion clause are true?
Check all of the boxes that apply.Which of the following statements about the First Amendment’s religion clause are true?
Check all of the boxes that apply.
Answer:
r≤0
Step-by-step explanation:
if the range is s≤0, (that means the value of s is all negative integers &0) to find the domain we have to replace that some negative integers &0.
we can replace some values of s as the following
s=‒4(0)^2 s=‒4(‒1)^2
=‒4(0) =‒4(1)
=0 =‒4
s=‒4(‒2)^2 s=‒4(‒3)^2
=‒4(4) =‒4(9)
=‒16 =‒36
so we can understand easly that the domain is negative integer&0,it can't be positive because the square of any integer is positive.
therefore the answer is r≤0
i think &i hope it is clear.
Answer:
f(x)=-18x^2
Step-by-step explanation:
Given:
1+Integral(f(t)/t^6, t=a..x)=6x^-3
Let's get rid of integral by differentiating both sides.
Using fundamental of calculus and power rule(integration):
0+f(x)/x^6=-18x^-4
Additive Identity property applied:
f(x)/x^6=-18x^-4
Multiply both sides by x^6:
f(x)=-18x^-4×x^6
Power rule (exponents) applied"
f(x)=-18x^2
Check:
1+Integral(-18t^2/t^6, t=a..x)=6x^-3
1+Integral(-18t^-4, t=a..x)=6x^-3
1+(-18t^-3/-3, t=a..x)=6x^-3
1+(6t^-3, t=a..x)=6x^-3
That looks great since those powers are the same on both side after integration.
Plug in limits:
1+(6x^-3-6a^-3)=6x^-3
We need 1-6a^-3=0 so that the equation holds true for all x.
Subtract 1 on both sides:
-6a^-3=-1
Divide both sides by-6:
a^-3=1/6
Raise both sides to -1/3 power:
a=(1/6)^(-1/3)
Negative exponent just refers to reciprocal of our base:
a=6^(1/3)
Answer:
1/18
Step-by-step explanation:
First make it so they all have the same denominator.
So...
2 3/18 - (- 48/18) + (- 4 14/18)
Then we remove parenthesis...
2 3/18 +48/18 - 4 4/18
1/18
hope this helps
brainliest?
Answer: each pound of jelly beans costs 1.5 dollars, or $1.50, and each pound of trail mix costs 2 dollars, or $2
Step-by-step explanation:
j = jellybeans
t = trail mix
2j + 5t = 13
8j + 3t = 18
To solve this, we want to isolate a variable, and solve for the other. Let's do that with each equation.
2j + 5t = 13
2j = 13 - 5t
j = (13 - 5t) / 2
8j + 3t = 18
8j = 18 - 3t
j = (18 - 3t) / 8
Now that we have isolated the variable j in each equation, we can set the two right-sides equal to each other, and solve for t.
(13 - 5t) / 2 = (18 - 3t) / 8
By multiplying both sides by 8, this becomes simpler to look at.
8 * (13 - 5t) / 2 = 18 - 3t
4 * (13 - 5t) = 18 - 3t
4 * 13 - 4 * 5t = 18 - 3t
52 - 20t = 18 - 3t
52 = 18 + 17t
34 = 17t
34 / 17 = t
t = 2
Now that we have solved for t, we can trivially plug it into one of the other equations to solve for j. Let's choose the first equation, as it doesn't matter which we choose.
t = 2
2j + 5t = 13
2j + 5 * 2 = 13
2j + 10 = 13
2j = 13 - 10
2j = 3
j = 1.5
So, each pound of jelly beans costs 1.5 dollars, or $1.50, and each pound of trail mix costs 2 dollars, or $2.
