Answer:
19/20- 0.95; 95%
9/16- 0.5625; 56%
0.4- 2/5; 40%
0.22- 22%; 11/50
Step-by-step explanation:
trust me
a) For this question we set h=59 and solve for t, in order to do so we use the general formula for second-degree equations:
![\begin{gathered} t=\frac{-124\pm\sqrt[]{124^2-4(-16)(-40)}}{2(-16)} \\ t=\frac{-124\pm113.21}{-32} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20t%3D%5Cfrac%7B-124%5Cpm%5Csqrt%5B%5D%7B124%5E2-4%28-16%29%28-40%29%7D%7D%7B2%28-16%29%7D%20%5C%5C%20t%3D%5Cfrac%7B-124%5Cpm113.21%7D%7B-32%7D%20%5Cend%7Bgathered%7D)
The height of the object will be 59 feet at t=7.41 seconds and t=0.34 seconds.
b) When the object reaches the ground, h=0 therefore:

Solving for t we get:
![\begin{gathered} t=\frac{-124\pm\sqrt[]{124^2-4(-16)(19)}}{2(-16)} \\ t=\frac{-124\pm\sqrt[]{16592}}{-32}=\frac{-124\pm128.81}{-32} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20t%3D%5Cfrac%7B-124%5Cpm%5Csqrt%5B%5D%7B124%5E2-4%28-16%29%2819%29%7D%7D%7B2%28-16%29%7D%20%5C%5C%20t%3D%5Cfrac%7B-124%5Cpm%5Csqrt%5B%5D%7B16592%7D%7D%7B-32%7D%3D%5Cfrac%7B-124%5Cpm128.81%7D%7B-32%7D%20%5Cend%7Bgathered%7D)
Therefore, since t cannot be negative the solution is t=7.9 seconds.
<h2>
Answer:</h2>
option: B is the correct answer.
B. complex numbers.
<h2>
Step-by-step explanation:</h2>
We know that a complex number is always written in the form of :
a+ib
where a and b are real numbers and i is the square root of -1.
i is called an imaginary number.
If a>0 and b>0 then the point lie in the first quadrant.
if a>0 and b<0 then the point lie in the fourth quadrant.
if a<0 and b>0 then the point lie in the second quadrant.
if a<0 and b<0 then the point lie in the third quadrant.
Answer:
Step-by-step explanation:

GFC: 2g
We'll Write the GCF first, then, divide each term by the GCF.

