All categories

3 years ago

The value of a certain rare stamp is 160% of its value three years ago if the stamp is worth $220 then what is it’s worth today

Mathematics

2 answers:

xz_007 [3.2K]3 years ago

6 0

Answer:

572$

Step-by-step explanation:

100% of 220 is 220 so add them together. Then find 60 % of 220. To find 10% of a number move the decimal to the left one time. Which is 22. After that, multiply 22 by 6 because it's 60%. then ad 220+220+132=572.

mariarad [96]3 years ago

6 0

Answer:

$352

Step-by-step explanation:

everyone is sayin 572 but IT IS WRONG trust me i have this worksheet... IT IS... $352

You might be interested in

How much does a 5 lb 11 oz roast weigh in grams?

Maurinko [17]

Answer:

2268 grams or 2 kg 268 g

Step-by-step explanation:

How to convert Pounds to Grams

1 pound (lb) is equal to 453.59237 grams (g).

1 lb = 453.59237 g

The mass m in grams (g) is equal to the mass m in pounds (lb) times 453.59237:

m(g) = m(lb) × 453.59237

In this case,

Convert 5 lb to grams:

2267.96 approximately convert to nearest thousands.

m(g) = 5 lb × 453.59237 = 2268 g or 2 kg 268 g

5 0

3 years ago

Read 2 more answers

Can you please help me with this, I have no idea

sergejj [24]

I have no clue sorry

6 0

3 years ago

If the sphere shown above has a radius of 14 units then what is the approximate volume of the sphere

oksano4ka [1.4K]

Answer:

About 11494.04

Step-by-step explanation:

There is no sphere shown above but I can still get you the answer:

The formula for the volume of a sphere is $\frac{4}{3} *$ π*r³

Putting in the radius, we get:

$\frac{4}{3}$ *π*14³=

$\frac{4}{3}$ *π*2744=

$\frac{10976}{3}$ *π=

3658.66*π≈11494.04

8 0

3 years ago

Evaluate the integral, show all steps please!

Aloiza [94]

Answer:

$\displaystyle \int \dfrac{1}{(9-x^2)^{\frac{3}{2}}}\:\:\text{d}x=\dfrac{x}{9\sqrt{9-x^2}} +\text{C}$

Step-by-step explanation:

Fundamental Theorem of Calculus

$\displaystyle \int \text{f}(x)\:\text{d}x=\text{F}(x)+\text{C} \iff \text{f}(x)=\dfrac{\text{d}}{\text{d}x}(\text{F}(x))$

If differentiating takes you from one function to another, then integrating the second function will take you back to the first with a constant of integration.

Given indefinite integral:

$\displaystyle \int \dfrac{1}{(9-x^2)^{\frac{3}{2}}}\:\:\text{d}x$

Rewrite 9 as 3² and rewrite the 3/2 exponent as square root to the power of 3:

$\implies \displaystyle \int \dfrac{1}{\left(\sqrt{3^2-x^2}\right)^3}\:\:\text{d}x$

Integration by substitution

$\boxed{\textsf{For }\sqrt{a^2-x^2} \textsf{ use the substitution }x=a \sin \theta}$

$\textsf{Let }x=3 \sin \theta$

$\begin{aligned}\implies \sqrt{3^2-x^2} & =\sqrt{3^2-(3 \sin \theta)^2}\\ & = \sqrt{9-9 \sin^2 \theta}\\ & = \sqrt{9(1-\sin^2 \theta)}\\ & = \sqrt{9 \cos^2 \theta}\\ & = 3 \cos \theta\end{aligned}$

Find the derivative of x and rewrite it so that dx is on its own:

$\implies \dfrac{\text{d}x}{\text{d}\theta}=3 \cos \theta$

$\implies \text{d}x=3 \cos \theta\:\:\text{d}\theta$

Substitute everything into the original integral:

$\begin{aligned}\displaystyle \int \dfrac{1}{(9-x^2)^{\frac{3}{2}}}\:\:\text{d}x & = \int \dfrac{1}{\left(\sqrt{3^2-x^2}\right)^3}\:\:\text{d}x\\\\& = \int \dfrac{1}{\left(3 \cos \theta\right)^3}\:\:3 \cos \theta\:\:\text{d}\theta \\\\ & = \int \dfrac{1}{\left(3 \cos \theta\right)^2}\:\:\text{d}\theta \\\\ & = \int \dfrac{1}{9 \cos^2 \theta} \:\: \text{d}\theta\end{aligned}$

Take out the constant:

$\implies \displaystyle \dfrac{1}{9} \int \dfrac{1}{\cos^2 \theta}\:\:\text{d}\theta$

$\textsf{Use the trigonometric identity}: \quad\sec^2 \theta=\dfrac{1}{\cos^2 \theta}$

$\implies \displaystyle \dfrac{1}{9} \int \sec^2 \theta\:\:\text{d}\theta$

$\boxed{\begin{minipage}{5 cm}\underline{Integrating $\sec^2 kx$}\\\\$\displaystyle \int \sec^2 kx\:\text{d}x=\dfrac{1}{k} \tan kx\:\:(+\text{C})$\end{minipage}}$