395,000,000 i think not sure
Y=(-1/6)x+5
m=(y2-y1)/(x2-x1)
m=(3-6)/(12-(-6))
m=(-3)/(18)
m=-1/6
y=mx+b
y=(-1/6)x+b
6=(-1/6)(-6)+b
6=1+b
b=5
y=(-1/6)x+5
Answer: There is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.
Step-by-step explanation:
Total number of students = 8
Number of student who has passed Exam P/1 = 1
Number of student who has passed Exam FM/2 = 1
No student has passed more than one exam.
According to question, exactly three students from a randomly chose group of four students have not passed Exam P/1 or Exam FM/2.
So, Probability will be

Hence, there is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.
Answer:
<PCH+<HCK=180-DEGREE BEING IN A STRAIGHT LINE.
3M+58+8M+155=180
11M=180-213
11M=-33
M=-3
SO,
<PCH
3M+58
=3*(-3)+58
=58-9
=49-DEGREE
Answer:
Ashley uses internal citation to give credit for someone else's idea