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andre [41]
3 years ago
10

A businessman borrowed P3,000,000 with interest at the rate of 6% compounded annually. He agrees to discharge his obligations by

paying a series of 6 annual payment, the first being due at the end of the fifth year. Determine the value of his annual payment. A. 500,000 B. 770,222 C. 726,625 D. 600,000
Mathematics
1 answer:
Elis [28]3 years ago
7 0

Answer:

B. 770,222

Step-by-step explanation:

From the question above, we are given the following values:

Principal = 3,000,000

Interest rate = 6%

Step 1

Since we are told in the question that he will make 6 payments at the end of each year STARTING FROM THE END OF THE FIRTH YEAR, the first step would be to find the future value of the Principal (3,000,000) for the first 4 years.

Future Value formula =

FV = P × {(1 + r)ⁿ

Where P = Principal = 3,000,000

r = interest rate = 6% = 0.06

n = number of years = 4 years

Future value = 3,000,000 × {( 1 + 0.06)⁴

Future value = 3,787,430.88

Hence, the future value of this loan at the end of year 4 is 3,787,430.88.

Step 2

We are told in the question that he would be carrying out a series of series of 6 annual payment, the first being due at the end of the fifth year.

Therefore, this means the future value at the end of four year would be equal to or equivalent to the present value at the beginning of the fifth year.

The second step to take would be to find the periodic payment.

The forward for periodic payment is given as:

Periodic Payment ( Pmt) = (PV × r) ÷ ( 1 - (1 + r) ⁻ⁿ  

Present value( PV) = 3,787,430.88.

number of time periods = 6

interest rate per time period(r) = 6%

payments are made at the end of each time period.

Periodic Payment ( Pmt) = (3,787,430.88. × 0.06) ÷ [( 1 - (1 + 0.06)⁻⁶)]

= 770,221.9

Approximately = 770,222

Therefore, the value of his annual payment with his first payment been due at the beginning of the fifth year is 770,222.

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Step-by-step explanation:

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.A variety of stores offer loyalty programs. Participating shoppers swipe a bar-coded tag at the register when checking out and
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Answer:

a) Null hypothesis:\mu \leq 120  

Alternative hypothesis:\mu > 120  

b) t=\frac{130-120}{\frac{40}{\sqrt{80}}}=2.236  

The degrees of freedom are given by:

df = n-1 = 80-1=79

The p value for this case taking in count the alternative hypothesis would be:

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Step-by-step explanation:

Information given

\bar X=130 represent the sample mean for the amount spent each shopper

s=40 represent the sample standard deviation

n=80 sample size  

\mu_o =120 represent the value to verify

t would represent the statistic    

p_v represent the p value f

Part a

We want to verify if the shoppers participating in the loyalty program spent more on average than typical shoppers, the system of hypothesis would be:  

Null hypothesis:\mu \leq 120  

Alternative hypothesis:\mu > 120  

The statistic for this case would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

Replacing the info given we got:

t=\frac{130-120}{\frac{40}{\sqrt{80}}}=2.236  

The degrees of freedom are given by:

df = n-1 = 80-1=79

The p value for this case taking in count the alternative hypothesis would be:

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4 years ago
To be considered for pilot school, 12 students took a spatial reasoning test that resulted in this list of scores. Find the valu
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Answer:

the 90th percentile is 145

Step-by-step explanation:

Data provided:

152 121 130 143 122 101 137 98 138 127 145 117

Number of students considered, n = 12

To find:

90th percentile

Now,

Step 1 : Arrange the data in ascending order

98, 101, 117, 121, 122, 127, 130, 137, 138, 143, 145, 152

Step 2 : Compute the position of the 90th percentile

position of the 90th percentile, i = (90% × n)

Thus,

i = 0.90 × 12

or

i = 10.8

Now,

Step 3 : Since, the index i is not an integer, round up to the nearest integer

i.e i = 11

Therefore,

The 90th percentile is the value in 11th position,

i.e 145

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Marysya12 [62]

Answer:

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