A 0.7834 g sample of a primary standard KHP was titrated with 38.45 mL of NaOH solution to a phenolphthalein end-point. What is the molarity of the NaOH solution?
1 answer:
Answer:
0.0998 M
Explanation:
KHP is a weak <em>monoprotic</em> acid. This means that t<u>he moles of acid are equal to the moles of OH⁻ that were added in the titration</u>.
KHP Molecular weight = 204.22 g/mol
moles KHP = 0.7834 g ÷ 204.22 g/mol = 3.836x10⁻³ mol KHP So 3.836x10⁻³ moles of OH⁻ were added in the titration. With moles and volume we can <u>calculate the molarity of the NaOH solution</u>:
38.45 mL ⇒ 38.45/1000 = 0.03845 L
3.836x10⁻³ mol OH⁻ / 0.03845 L = 0.0998 M
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