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nadya68 [22]
3 years ago
6

Help ! Easy 7th grade work ! I’ll give brainliest!

Mathematics
1 answer:
balu736 [363]3 years ago
5 0

Answer:

Step-by-step explanation:

a.  2415

b.  3124

c. 627

d. 8

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FIND PRODUCT USING THIS AREA MODEL 300+70+8 AND WRITE THE EQUATION
Dmitrij [34]

Answer:

378

Step-by-step explanation:

300

 70

   8

+-------

378

8 0
3 years ago
Help me please !!!!!!
PilotLPTM [1.2K]
The correct answer is B. x is greater than -2.

7 0
3 years ago
An experienced landscaper can landscape garden with an area of 60sq.m thrice as fast as an apprentice. Working together, it take
Genrish500 [490]

Answer:

It will take the apprentice 24 days working alone

Step-by-step explanation:

Let the number of days it takes the apprentice be x

It will take the landscaper x/3 ( since he is three times faster)

The rate for both will be 60/6 = 10 sq m per day

Rate for apprentice is 60/x

rate for the boss is 60/x/3 = 180/x

Adding the rates together;

60/x + 180/x = 10

240/x = 10

240 = 10x

x = 240/10

x = 24 days

7 0
3 years ago
Can someone help me answer the above question paper​
Oxana [17]

Answer:

need teachers help with this one

Step-by-step explanation:

7 0
3 years ago
Find side lengths C and H
Nuetrik [128]

Answer:

\displaystyle c=\frac{2\sqrt{3}}{3}\\\\\displaystyle h=7\sqrt{2}\\

Step-by-step explanation:

<u>Right Triangles</u>

A right triangle can be identified by the fact it has an internal angle of 90°. In a right triangle, the trigonometric ratios stand.

Let's consider the triangle to the left.  We need to calculate side c, one of the legs of the triangle. We can use the angle adjacent to it (60°) or the angle opposite to it (30°) with the appropriate trigonometric ratio.

We'll use the adjacent angle, and

\displaystyle tan60^o=\frac{2}{c}

Solving for c

\displaystyle c=\frac{2}{tan60^o}=\frac{2}{\sqrt{3}}

Rationalizing

\displaystyle c=\frac{2}{\sqrt{3}}\cdot \frac{\sqrt{3}}{\sqrt{3}}=\frac{2\sqrt{3}}{3}

Now for the triangle to the right. The side h is the hypotenuse. Again, any of the two angles can be used (though they are equal, for it's an isosceles triangle). For any of them it is true that

\displaystyle sin45^o=\frac{7}{h}

Solving for h

\displaystyle h=\frac{7}{sin45^o}=\frac{7}{\frac{\sqrt{2}}{2}}=\frac{14}{\sqrt{2}}

Rationalizing

\displaystyle h=\frac{14}{\sqrt{2}}\cdot \frac{\sqrt{2}}{\sqrt{2}}=\frac{14\sqrt{2}}{2}=7\sqrt{2}

3 0
4 years ago
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