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sveticcg [70]
3 years ago
7

Angle VSU and TSR are what kind of angles?

Mathematics
1 answer:
Anit [1.1K]3 years ago
6 0

In this question, we have two angles given, which are

\angle VSU \ and \ \angle TSR

And we have to find the relationship between those two angles .

Let's first check what are Vertically Opposite Angles

They are the angles opposite to each other when two lines crossing each other .

And the given angles are formed by the two lines crossing each other and these angles are opposite to each other. So these angles are Vertically Opposite Angles .

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Answer:

I’m not sure.

Step-by-step explanation:

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The figure is made up of a hemisphere and a cylinder.
Goryan [66]
Data: (Cylinder)
h (height) = 8 cm
r (radius) = 5 cm
Adopting: \pi \approx 3.14
V (volume) = ?

Solving:(<span>Cylinder volume)
</span>V = h* \pi *r^2
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\boxed{ V_{cylinder}  = 628\:cm^3}

<span>Note: Now, let's find the volume of a hemisphere.
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Data: (hemisphere volume)
V (volume) = ?
r (radius) = 5 cm
Adopting: \pi \approx 3.14

If: We know that the volume of a sphere is V = 4 * \pi *  \frac{r^3}{3}, but we have a hemisphere, so the formula will be half the volume of the hemisphere V =  \frac{1}{2}  * 4 * \pi *  \frac{r^3}{3} &#10;

Formula: (<span>Volume of the hemisphere)
</span>V = \frac{1}{2} * 4 * \pi * \frac{r^3}{3}

Solving:
V = \frac{1}{2} * 4 * \pi * \frac{r^3}{3}
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<span>Now, to find the total volume of the figure, add the values: (cylinder volume + hemisphere volume)
</span>
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Volume of the figure = 628 cm³ + 261.6 cm³
\boxed{\boxed{Volume\:of\:the\:figure = 1517.6\:cm^3}}\end{array}}\qquad\quad\checkmark
3 0
3 years ago
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Find the solution of 4x2y′′−4x2y′+y=0,x&gt;04x2y″−4x2y′+y=0,x&gt;0 of the form y1=xr(1+c1x+c2x2+c3x3+⋯)
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Answer:

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Step-by-step explanation:

Find the solution of 4x2y′′−4x2y′+y=0,x>04x2y″−4x2y′+y=0,x>0 of the form y1=xr(1+c1x+c2x2+c3x3+⋯)

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Answer:

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