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3 years ago

Angle VSU and TSR are what kind of angles?

Mathematics

1 answer:

Anit [1.1K]3 years ago

6 0

In this question, we have two angles given, which are

$\angle VSU \ and \ \angle TSR$

And we have to find the relationship between those two angles .

Let's first check what are Vertically Opposite Angles

They are the angles opposite to each other when two lines crossing each other .

And the given angles are formed by the two lines crossing each other and these angles are opposite to each other. So these angles are Vertically Opposite Angles .

You might be interested in

An isosceles triangle has a base of 8 inches and legs measuring 12 inches how wide is the base of a similar triangle with legs m

VARVARA [1.3K]

If the triangles are similar, the base should be 24 inches. The legs on the first triangle are 12 inches. To get 36 inches (the other triangle), we multiply 12 by 3. 12 x 3 = 36. Because you did that to the legs, you must also do it to the base. 8 x 3 = 24. Therefore, the base of the second triangle is 24 inches.

5 0

4 years ago

Here's the question.

OleMash [197]

Answer:

The value of T₂₀ - T₁₅ is -20.

Step-by-step explanation:

Given :

>> If for an A.P, d = -4

To Find :

>> T₂₀ - T₁₅

Using Formula :

General term of an A.P.

$\star{\small{\underline{\boxed{\sf{\red{ T_n = a + (n - 1)d}}}}}}$

>> Tₙ = nᵗʰ term
>> a = first term
>> n = no. of terms
>> d = common difference

Solution :

Firstly finding the A.P of T₂₀ by substituting the values in the formula :

${\dashrightarrow{\pmb{\sf{ T_n = a + (n - 1)d}}}}$

${\dashrightarrow{\sf{ T_{20} = a + (20 - 1) d}}}$

${\dashrightarrow{\sf{ T_{20} = a + (19)d}}}$

${\dashrightarrow{\sf{ T_{20} = a + 19 \times d}}}$

${\dashrightarrow{\sf{ T_{20} = a + 19d}}}$

${\star \: {\underline{\boxed{\sf{\pink{ T_{20} = a + 19d}}}}}}$

Hence, the value of T₂₀ is a + 19d.

$\rule{190}1$

Secondly, finding the A.P of T₁₅ by substituting the values in the formula :

${\dashrightarrow{\pmb{\sf{ T_n = a + (n - 1)d}}}}$

${\dashrightarrow{\sf{ T_{15}= a + (15 - 1) d}}}$

${\dashrightarrow{\sf{ T_{15}= a + (14) d}}}$

${\dashrightarrow{\sf{ T_{15}= a + 14 \times d}}}$

${\dashrightarrow{\sf{ T_{15}= a + 14d}}}$

${\star{\underline{\boxed{\sf \pink{ T_{15}= a + 14d}}}}}$

Hence, the value of T₁₅ is a + 14d

$\rule{190}1$

Now, finding the difference between T₂₀ - T₁₅ :

${\dashrightarrow{\pmb{\sf{T_{20} - T_{15}}}}}$

${\dashrightarrow{\sf{(a + 19d) - (a + 14d)}}}$

${\dashrightarrow{\sf{a + 19d - a - 14d}}}$

${\dashrightarrow{\sf{a - a + 19d - 14d}}}$

${\dashrightarrow{\sf{0+ 19d - 14d}}}$

${\dashrightarrow{\sf{19d - 14d}}}$

${\dashrightarrow{\sf{5 \times - 4}}}$

${\dashrightarrow{\sf{ - 20}}}$

${\star \: \underline{\boxed{\sf{\pink{T_{20} - T_{15} = - 20}}}}}$

Hence, the value of T₂₀ - T₁₅ is -20.

$\underline{\rule{220pt}{3.5pt}}$

3 0

3 years ago

Below are two different functions, f(x) and g(x). What can be determined about their y-intercepts? F(x)=-2x-1

katrin [286]

The function g(x) has a higher y intercept

3 0

3 years ago

Read 2 more answers

If a ladder is 5.5 m long and it is placed 3 m from the wall, solve and show the work when you use the Pythagorean Theorem to fi

natali 33 [55]

Answer:

4.609 meters

Step-by-step explanation:

The hypotenuse is the ladder because it is the slanted side. 3m is one of the other side lengths

A^2 + B^2 = C^2

3^2 + B^2 = 5.5^2

9 + B^2 = 30.25

30.25 - 9= B^2

21.25= B^2

4.609=B

4 0

3 years ago

Will mark first answer brainliest

babymother [125]

Answer:

Step-by-step explanation:

B. -3

Hope that helps!

8 0

3 years ago

Read 2 more answers