Let i = sqrt(-1) which is the conventional notation to set up an imaginary number
The idea is to break up the radicand, aka stuff under the square root, to simplify
sqrt(-8) = sqrt(-1*4*2)
sqrt(-8) = sqrt(-1)*sqrt(4)*sqrt(2)
sqrt(-8) = i*2*sqrt(2)
sqrt(-8) = 2i*sqrt(2)
<h3>Answer is choice A</h3>
y2-y1 / x2-x1
7-3 / 4-1
4/3
1 & 1/3 should be correct
Ignore my answer for b, but all the rest are correct. a: about 2.94 c:12.24 cm
Answer:
b) Yes, the triangles are similar by the SSS similarity
