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Arte-miy333 [17]
3 years ago
10

Which of the following expressions are equivalent to 4x-6+8x+2

Mathematics
2 answers:
Len [333]3 years ago
8 0

Answer:

A) 12x - 4  and  B)  4(3x - 1)

Step-by-step explanation:

You have to combine like terms to solve this problem.   Any terms with the same variable are like terms, and all constants are like terms.

  4x - 6 + 8x  + 2          

   

          Here, 4x and 8x are like terms, so are -6 and 2, so we group them together

   4x + 8x - 6 + 2

Now simplify

     12x - 4             (4x + 8x = 12x, there are 4 'x's and you add 8 more 'x's,

                               you have -6 and add 2 to it).  This is answer A

Each of these terms has a multiple of 4, so we can factor that term out to get answer B

 4(3x - 1)             (12x/4 = 3x, and -4/4 = 1)  

exis [7]3 years ago
7 0

Answer:

A) 12x-4

and B) 4(3x-1)

Step-by-step explanation:

4x-6+8x+2

Rearrange the question

4x+8x-6+2

12x-4

B because when you simplify the equation 4(3x-1) = 12x-4

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I need help again /:
givi [52]

Step-by-step explanation:

I would go with a or b but one sec let me work it out

4 0
2 years ago
Plz help me .................
11Alexandr11 [23.1K]

Answer:

15%

Step-by-step explanation:

Question:

The price of a jacket was slashed from Rs.960 to Rs.816.Then the rate of discount offered is​

Solution

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Difference in price=Original price - discount price

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=Rs. 144

Percentage discount= Difference in price / Original price × 100

=Rs. 144 / Rs. 960 × 100

=0.15 × 100

=15%

The percentage discount =15% NOT 10% as you have written

4 0
2 years ago
Determine if the lim f(x) exists using the graph below.. If it does, find its value. If it does not,x 1explain why
Leno4ka [110]

The limit of a function f at a point a exists if:

\lim_{x\to a^-}f(x)=\lim_{x\to a^+}f(x)\begin{gathered} \text{ From the given image, the value of the left limit of f at x=1 } \\ \lim_{x\to a^-}f(x)\lt1 \end{gathered}

Also,

\begin{gathered} \text{ From the given image, the value of the right limit of f at x=1 } \\ \lim_{x\to a^+}f(x)\gt1 \end{gathered}

Therefore,

\lim_{x\to1^-}f(x)\lim_{x\to1^+}f(x)

Hence, the limit does not exist

8 0
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andreev551 [17]

Answer:

4/6 and 1/6

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

8 0
3 years ago
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