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tensa zangetsu [6.8K]
3 years ago
7

Blaire needs more than 616 total points on assignments in her math class to pass. She only has 224 points and needs to do some e

xtra credit assignments that are worth 56 points each.
56x + 224 > 616

How many extra credit assignments does Blaire need to complete in order to pass?
A.
x > 56
B.
x > 7
C.
x > 392
D.
x > 224
Mathematics
1 answer:
jek_recluse [69]3 years ago
4 0

Answer: The answer is x >7

Step-by-step explanation:

56⋅x>616−224

56⋅x>616-224

Simplify :

56⋅x>392

56⋅x>392

Dividing by the variable coefficient :

x>

392

56

x>39256

Simplify :

x>7

x>7

Inequality  

56⋅x+224>616

56⋅x+224>616

is true for  

x>7

x>7

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scoray [572]

Answer18:

The quadrilateral ABCD is not a parallelogram

Answer19:

The quadrilateral ABCD is a parallelogram

Step-by-step explanation:

For question 18:

Given that vertices of a quadrilateral are A(-4,-1), B(-4,6), C(2,6) and D(2,-4)

The slope of a line is given m=\frac{Y2-Y1}{X2-X1}

Now,

The slope of a line AB:

m=\frac{Y2-Y1}{X2-X1}

m=\frac{6-(-1)}{(-4)-(-4)}

m=\frac{7}{0}

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The slope of a line BC:

m=\frac{Y2-Y1}{X2-X1}

m=\frac{6-6}{(-4)-(-1)}

m=\frac{0}{(-3)}

The slope is zero degree

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m=\frac{Y2-Y1}{X2-X1}

m=\frac{(-4)-6}{2-2}

m=\frac{-10}{0}

The slope is 90 degree

The slope of a line DA:

m=\frac{Y2-Y1}{X2-X1}

m=\frac{(-1)-(-4)}{(-4)-(2)}

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The slope of the only line AB and CD are the same.

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For question 19:

Given that vertices of a quadrilateral are A(-2,3), B(3,2), C(2,-1) and D(-3,0)

The slope of a line is given m=\frac{Y2-Y1}{X2-X1}

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m=\frac{Y2-Y1}{X2-X1}

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m=\frac{Y2-Y1}{X2-X1}

m=\frac{(-1)-2}{2-3}

m=\frac{-3}{-1}

m=3

The slope of a line CD:

m=\frac{Y2-Y1}{X2-X1}

m=\frac{0-(-1)}{(-3)-2}

m=\frac{-1}{5}

The slope of a line DA:

m=\frac{Y2-Y1}{X2-X1}

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The slope of the line AB and CD are the same

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