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3 years ago

If f(x)=e* and g(x) = X-4, what is (gºf)(x)?

Mathematics

1 answer:

shtirl [24]3 years ago

3 0

Answer:

Step-by-step explanation:

because i took the test on edge.

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Find the angle between the given vectors. Round your answer, in degrees, to two decimal places. u=⟨2,−6⟩u=⟨2,−6⟩, v=⟨4,−7⟩

NISA [10]

Answer:

$\theta = 108.29$

Step-by-step explanation:

Given

$u =$

$v =$

Required:

Calculate the angle between u and v

The angle $\theta$ is calculated as thus:

$cos\theta = \frac{u.v}{|u|.|v|}$

For a vector

$A =$

$A = a * b$

$cos\theta = \frac{u.v}{|u|.|v|}$ becomes

$cos\theta = \frac{.}{|u|.|v|}$

$cos\theta = \frac{2*6+4*-7}{|u|.|v|}$

$cos\theta = \frac{12-28}{|u|.|v|}$

$cos\theta = \frac{-16}{|u|.|v|}$

For a vector

$A =$

$|A| = \sqrt{a^2 + b^2}$

So;

$|u| = \sqrt{2^2 + 6^2}$

$|u| = \sqrt{4 + 36}$

$|u| = \sqrt{40}$

$|v| = \sqrt{4^2+(-7)^2}$

$|v| = \sqrt{16+49}$

$|v| = \sqrt{65}$

So:

$cos\theta = \frac{-16}{|u|.|v|}$

$cos\theta = \frac{-16}{\sqrt{40}*\sqrt{65}}$

$cos\theta = \frac{-16}{\sqrt{2600}}$

$cos\theta = \frac{-16}{\sqrt{100*26}}$

$cos\theta = \frac{-16}{10\sqrt{26}}$

$cos\theta = \frac{-8}{5\sqrt{26}}$

Take arccos of both sides

$\theta = cos^{-1}(\frac{-8}{5\sqrt{26}})$

$\theta = cos^{-1}(\frac{-8}{5 * 5.0990})$

$\theta = cos^{-1}(\frac{-8}{25.495})$

$\theta = cos^{-1}(-0.31378701706)$

$\theta = 108.288386087$

<em></em> $\theta = 108.29$ <em> (approximated)</em>

4 0

2 years ago

4 + x = 12 solve equation ///ASAP /// WILL MARK BRAINLIEST

Bess [88]

Answer:

Answer is 8.

Step-by-step explanation: 12-4=8 so 4+8=12

hoped this helped you

4 0

3 years ago

The lines below are parallel. If the slope of the green line is -2, what is the slope of the redline?

scoray [572]

D. -2, if the lines are parallel then the slope is the same but the y-int is different

3 0

3 years ago

Please help!!!!!!!!!!!

IRISSAK [1]

Answer:

Step-by-step explanation:

4 0

3 years ago

(HELP! I HAVE NO TIME) At 2pm, a store had sold 15 packs of toilet paper. By 5pm, the store had sold 57 packs of toilet paper. W

Novay_Z [31]

$\mathrm {Hey, there!}$

Let's solve your problem:

The answer would be 280%.

We know the following information:

2pm - 15 toilet paper rolls

5pm - 57 toilet paper rolls

We have to find the <u>percent rate of change.</u>

Here is how we will do this problem:

<h3><u>First, Set up a ratio:</u></h3>

Change in the quantity [15 - 57]

-------------------------------------

Original quantity [15]

57 - 15 = 42

<h3><u>Next, we will divide. the ratio.</u></h3>

Given quantity - 42

Number of packs sold at 2pm - 15

Fraction - 42/15

<h3><u>Convert the fraction to a decimal.</u></h3>

Fraction - 42/15

Decimal - 2.8

<h3><u>Make the decimal to a percent.</u></h3>

Decimal - 2.8

Percent - 28%

<h2><u>Our answer is 280%</u></h2>

4 0

3 years ago

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