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3 years ago

URGENT! PLEASE HELP!! I WON'T HESITATE TO MARK BRAINLIEST FOR FIRST CORRECT ANSWER!!!

Mathematics

1 answer:

Aliun [14]3 years ago

8 0

Answer:

A(2/3, 6)

B(15, 33)

Slope=81/43

Step-by-step explanation:

If for the first point A Y=6, you can just plug it into the spot for the Y in the equation.

So that get's you the equation 6-2x=3

Solving the equation you get:

2x=3

x=2/3

So that means that for point A your coordinate pair is (2/3, 6)

You do the same for B.

B has point X=15, so plug it in:

y-2(15)=3

y-30=3

y=33

So your coordinate pair for B is (15, 33)

Then to find the slope you follow the equation y2-y1/x2-x1

Plugging in the numbers you get:

33-6/15-2/3

27/43/3

81/43

So your slope=81/43

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2 years ago

Which is the simplified form of the expression ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript nega

AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

To find the simplified form of the given expression :

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

$=(2^{-2})^{-3}(3^4)^{-3}\times (2^{-3})^2(3^2)^2$ ( using the property $(ab)^m=a^m.b^m$ )

$=(2^6)(3^{-12})\times (2^{-6})(3^4)$ ( using the property $(a^m)^n=a^{mn}$

$=(2^6)(2^{-6})(3^{-12})(3^4)$ ( combining the like powers )

$=2^{6-6}3^{-12+4}$ ( using the property $a^m.a^n=a^{m+n}$ )

$=2^03^{-8}$

$=\frac{1}{3^8}$ ( using the property $a^{-m}=\frac{1}{a^m}$ )

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Therefore option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

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