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Scrat [10]
3 years ago
11

Find the slope intercept form for the equation of the line which passes through the point (-4,-14) and has a slope of 1

Mathematics
1 answer:
Fudgin [204]3 years ago
5 0
Use point slope form to answer this
Y = x - 10

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Write an equation ​(a) in​ slope-intercept form and ​(b) in standard form for the line passing through ​(22​,99​) and perpendicu
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Y-99=-1/33(x-22)

a). y = 1/33x + 98 1/3

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3 years ago
I need to find the perimeter and area of the regular polygon.
mezya [45]
The area of a polygon is given by the formula Area = ap/2 where a is the length of the apothem and p is the perimeter. The apothem is a line from the center of the polygon perpendicular to a side.

Depending on the formula you know, you can find the length of a side in 1 of 2 ways. 

The first way uses a triangle. Using the radius of the polygon you can create 8 congruent triangles. The center angle will be 360 / 8 = 45 and two side lengths of 20. You can find the length of the base using the law of cosines.

c^2 = 20^2 + 20^2 - 2(20)(20)(cos 45)
c^2 = 400 + 400 - 800(cos 45)
c^2 = 800 - 800(cos 45)
c = sqrt(800 - 800(cos 45)
c = 15.31

The second way is to use this formula:
r = s / (2 sin(180 / n))
20 = s / (2 sin(180/8)
(20)(2)sin(22.5) = s
(40)sin(22.5) = s
s = 15.31

We need to calculate the perimeter. As there are 8 sides (8)(15.31) = 122.48
Now we need to calculate the apothem using

a = S / (2 tan (180 / n)
a = 15.31 / (2 tan (180 / 8))
a = 18.48

Now solve for the area

Area = ap/2
Area = (18.48)(122.48)/2
Area = 1131.72

perimeter = 122.48
area = 1131.72
7 0
3 years ago
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