The question is asking that given point k and m is such then figure out point L. this shouldn't be the whole question. is there a diagram that comes with it?
The intersection point of the two lines is (2,1,0).
The respective direction vectors are
L1: <1,2,4>
L2: <4,1,15>
Since the normal vector of the required plane is perpendicular to both direction vectors, the normal vector of the plane is obtained by the cross product of L1 and L2.
i j k
1 2 4
4 1 15
=<30-4, 16-15, 1-8>
=<26, 1, -7>
We know that the plane must pass through (2,1,0), the equation of the plane is
26(x-2)+1(y-1)-7(z-0)=0
simplifying,
26x+y-7z=52+1+0=53
or
26x+y-7z=53
Check:
Put points on L1 in the plane
26(t+2)+(2t+1)-7(4t+0)=53 ok
For L2,
26(4t+2)+(t+1)-7(15t+0)=53 ok
Answer:
number of people=56320
Step-by-step explanation:
area of street=2×1760×3×6=63360 cm²
number of people={63360÷(3× 3)}× 8=7040× 9=56320
Answer:
Slope: -4
Y-intercept: 5
Step-by-step explanation:
The slope goes down 4 and over one which means that the slope is -4.
When X is 0, Y is 5
Good Luck!!
3 hours and 20 minutes minus 1 hour and 48 minuets equals an hour and 32 minutes. There are 60 minuets in an hour and 60 divided by 32 is 0.53. This means that your final answer is:
D. 1.53
