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3 years ago

How do u solve 8+(5square -3)divided by 11

Mathematics

1 answer:

saul85 [17]3 years ago

3 0

Answer:16

Step-by-step explanation: 8(25−3)÷11

8(22)

176 divided by 11= 16

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A slug travels 3 centimeters in 3 seconds. A snail travels 6 centimeters in 6 seconds. Both travel at constant speeds. Mai says,

ollegr [7]

Answer:

Mai is wrong since both travel the same distance in the same amount of seconds

Step-by-step explanation:

3 centimeters in 3 seconds is 1 centimeter a second for the slug

6 centimeters in 6 seconds is 1 centimeter a second for the snail

so both travel the same distance

5 0

3 years ago

Read 2 more answers

∠R and ∠S are complementary. If m∠R = (2x+7) and m∠S = (4x - 13), find m∠R

____ [38]

Answer:

m∠R = 39 degrees

Step-by-step explanation:

As complementary angles add up to 90 degrees, we can set up an equation to get x then find the measure of ∠R:

m∠R + m∠S = 90

2x+7+4x-13=90

6x+7-13=90

6x-6=90

6x=96

x=16

Since m∠R = (2x+7), 2x+7 would be 2(16)+7 or 39 degrees. So in conclusion, m∠R = 39 degrees

3 0

3 years ago

Read 2 more answers

john wanted to run a 26k marathon. He only completed 0.75 of it before having to stop . How many kilometers did he run

kvasek [131]

Answer:

19.5 kilometers

Step-by-step explanation:

to find how much he ran we can multiply the two numbers

26 * 0.75 is 19.5

he only ran 19.5 kilometers

6 0

2 years ago

Describe the error in the work shown below.

Katena32 [7]

Answer:

the bottom equation should be 18+30=3(6+10)

Step-by-step explanation:

6(3+10) = 18+60 which equals 78

78 does not equal 18

5 0

2 years ago

NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h ( t ) = − 4.

Oliga [24]

Answer:

$\displaystyle 1)48.2 \: \: \text{sec}$

$\rm \displaystyle 2)3021.6 \: m$

Step-by-step explanation:

<h3>Question-1:</h3>

so when flash down occurs the rocket will be in the ground in other words the elevation(height) from ground level will be 0 therefore,

to figure out the time of flash down we can set h(t) to 0 by doing so we obtain:

$\displaystyle - 4.9 {t}^{2} + 229t + 346 = 0$

to solve the equation can consider the quadratic formula given by

$\displaystyle x = \frac{ - b \pm \sqrt{ {b}^{2} - 4 ac} }{2a}$

so let our a,b and c be -4.9,229 and 346 Thus substitute:

$\rm\displaystyle t = \frac{ - (229) \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

remove parentheses:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

simplify square:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 4( - 4.9)(346)} }{2.( - 4.9)}$

simplify multiplication:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 6781.6} }{ - 9.8}$

simplify Substraction:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 45659.4} }{ - 9.8}$

by simplifying we acquire:

$\displaystyle t = 48.2 \: \: \: \text{and} \quad - 1.5$

since time can't be negative

$\displaystyle t = 48.2$

hence,

at 48.2 seconds splashdown occurs

<h3>Question-2:</h3>

to figure out the maximum height we have to figure out the maximum Time first in that case the following formula can be considered

$\displaystyle x _{ \text{max}} = \frac{ - b}{2a}$

let a and b be -4.9 and 229 respectively thus substitute:

$\displaystyle t _{ \text{max}} = \frac{ - 229}{2( - 4.9)}$

simplify which yields:

$\displaystyle t _{ \text{max}} = 23.4$

now plug in the maximum t to the function:

$\rm \displaystyle h(23.4)- 4.9 {(23.4)}^{2} + 229(23.4)+ 346$

simplify:

$\rm \displaystyle h(23.4) = 3021.6$

hence,

about 3021.6 meters high above sea-level the rocket gets at its peak?

5 0

2 years ago