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leva [86]
3 years ago
15

Find the slope that passes through the two points. (9,3) and (6,7)

Mathematics
1 answer:
JulijaS [17]3 years ago
7 0

Answer:

m=4/-3

Step-by-step explanation:

the equation for slope (m) when given two points is (y2-y1)/(x2-x1)

we are given the points (9,3) and (6,7)

we can label the points:

x1=9

y1=3

x2=6

y2=7

now substitute into the equation

m=(7-3)/(6-9)

subtract

m=4/-3

the slope is 4/-3

hope this helps!

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Answer:

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Step-by-step explanation:

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3 years ago
The volume of a cylinder is given by the formula V= πr^2h, where r is the radius of the cylinder and h is the height. Suppose a
AfilCa [17]

Answer:

V=π*(2x^3+35x^2+176x+192)units^3

Step-by-step explanation:

V=πr^2h

r=x+8

h=2x+3

V=π*(x+8)^2*2x+3

=π*(x^2+16x+64)*2x+3

=π*(2x^3+32x^2+128x+3x^2+48x+192)

=π*(2x^3+35x^2+176x+192)

Volume of the cylinder=π*(2x^3+35x^2+176x+192)units^3

7 0
3 years ago
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Hey guys I need your help ASAP
sineoko [7]

Answer:

18x^{3}+30x^{2}+42x+20

Step-by-step explanation:

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3 years ago
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A can of nacho cheese has a radius of 8 inches and a height of 4 inches. a can of
tatyana61 [14]

Answer:

8 inches

Step-by-step explanation:

Nacho cheese

v= Pi×radius×2×height

v = 3.14×8×2×4 = 200.96

jalapeño

3.14×4×2=25.12

200.96÷25.12=8

the height is 8

to check your work you can do

(multiply by 8 and see if it equals 200.96)

3.14×4×2×8 = 200.96

since the volume is the same as the volume for nacho cheese we can say that 8 inches for height is correct

8 0
3 years ago
What is the range of the function: h(x)=x+1/x^2 - 7x+10
Elina [12.6K]

Answer:

  (-∞, -1-(2/3)√2] ∪ [-1+(2/3)√2, ∞)

Step-by-step explanation:

To make it easier to differentiate, we'll rewrite the function as ...

  h(x) = 2/(x-5) -1/(x-2)

Then the derivative is ...

  h'(x) = -2/(x-5)^2 +1/(x-2)^2

This will be zero when ...

  -2(x-2)^2 +(x-5)^2 = 0

  -2(x^2 -4x +4) +(x^2 -10x +25) = 0

  -x^2 -2x +17 = 0

  x^2 +2x +1 = 17 +1

  x +1 = ±√18 = ±3√2

  x = -1 ±3√2

The values of the function at these locations are ...

  h(-1-3√2) = -1 +(2/3)√2 ≈ -1.9428

  h(-1+3√2) = -1 -(2/3)√2 ≈ -0.0572

Then the range of h(x) is ...

  (-∞, -1-(2/3)√2] ∪ [-1+(2/3)√2, ∞)

5 0
3 years ago
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