With reduction of order, we assume a solution of the form

, with

. Then


and substituting into the ODE gives



Let

, so that

. This gives the linear ODE

This equation is also separable, so you can write

Integrating both sides with respect to

gives


Next, solve

for

by integrating both sides again with respect to

.



And finally, solve for

.

and note that

is already taken into account as part of

, so this is the general solution to the ODE.
Answer:

Step-by-step explanation:

- With the equation's current format, we will have trouble solving with all these fractions. Especially the fraction
is very difficult to deal with, so my first step would be:

- If we multiply both sides by this number, we will be able to get rid of the messy fraction on the right side as well as remove the fraction on the left side. Like so:
- <em>I put the
I multiplied onto each side in fraction form simply for clarity. You do not need to do this.</em>

- After this point, let's put our variable,
, onto one side of this equation and any other integers on the other by adding and subtracting them from both sides.

- Now we divide so that
is isolated, and we are done.

Answer:7+a
Step-by-step explanation:multiply 7 by a
The answer is 20. you'll have to multiply 10 times 3 and get 30. Then you'll subtract the 10 from the 30 and get 20
LUFFY to the right and LUFFY to the left