Question

Can you help me with 8b and 8c and explain it please

Answer 1

Answer:

8b) 2x+$\sqrt{3}$x

8c) $\frac{x-3\sqrt{x} +2 }{x-4}$

Step-by-step explanation:

8b)

Multiply the top and bottom by 2+$\sqrt{3}$ to rationalize this fraction

$\frac{x}{2-\sqrt{3} } * \frac{2+\sqrt{3} }{2+\sqrt{3} }$

Simplify the product

$\frac{x(2+\sqrt{3}) }{1}$

Distribute x through the parenthesis

2x+$\sqrt{3}$x

8c)

Multiply the top and bottom by $\sqrt{x}-2$ to rationalize this fraction

$\frac{(\sqrt{x}-1)*(\sqrt{x}-2) }{(\sqrt{x}+2)*(\sqrt{x}-2) }$

Simplify the product

$\frac{x-2\sqrt{x}-\sqrt{x}+2 }{x-4}$

Collect like terms

$\frac{x-3\sqrt{x} +2 }{x-4}$