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Rasek [7]
3 years ago
8

Access to a computer can be controlled using a ____ password.

Computers and Technology
1 answer:
slamgirl [31]3 years ago
8 0
Yes it can be control by a USER ( administrator and having a MASTER password) 
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What type of coverage pays for damage incurred as a result of theft, vandalism, fire or natural disaster?
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Comprehensive or hazard insurance

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A coffee shop is considering accepting orders and payments through their phone app and have decided to use public key encryption
Charra [1.4K]

Answer: Yes

Explanation:

Public key encryption is the encryption technique that is used for private keys and public keys for securing the system.Public key is used for encryption and private key is for decryption.Public keys can only open content of the system

  • According to the question, public key encryption is secure for coffee shop customer payment process as they are stored on digital certificates in long form for verifying digital signature and encrypting information.Its computation is difficult to crack through power computer access.  
  • Other options is incorrect as encryption is not a problem for payment procedures. Thus, the correct option is yes ,public key encryption is secure method for coffee shop customers .
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3 years ago
Alonzo collects bugs. He has created a fascinating display of large insects. Collecting bugs is a(n) _____ to Alonzo.
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The answer is hobby. He does it because he enjoys it. There is no information of him being told or paid to collect bugs, so it is a hobby.
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3 years ago
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graphic design and digital marketing solutions

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3 years ago
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Compute the acceleration of gravity for a given distance from the earth's center, distCenter, assigning the result to accelGravi
SVETLANKA909090 [29]

Answer:

Replace /* Your solution goes here */ with the following expression

accelGravity = (G * M) / (distCenter *distCenter );

Explanation:

Required

Complete the code

The equivalent expression of (G * M) / (d^2) is:

(G * M) / (distCenter *distCenter );

The expression must be stored in accelGravity.

So, we have:

accelGravity = (G * M) / (distCenter *distCenter );

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