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Sophie [7]
3 years ago
5

What is the organizational management practices on planning during a pandemic like corona virus.

Computers and Technology
1 answer:
eduard3 years ago
3 0

Answer:

wear a mask use hand sanitizer dont get in contact with anyone between 6 feet

Explanation:

You might be interested in
java class What is the output of the following JAVA program (Java assumes public if no access modifier is given)? class Test { p
Natasha2012 [34]

Answer:

The answer to the given question is it will produce an "error"  

Explanation:

In the given java program it will produce an error because in java we do not use double quote("""") for message printing. We use a single quote("") for message printing. In the given program if we use a single quote(""). so it will give output that is "dogood:dogood".

The correct program to this question is can be given as:

Program:

public class Test  //define a class test.

{

   public static void main(String[] args)  //define main method

   {

       Test obj = new Test();   //create class object  

       obj.start(); //calling function

   }  

   void start()  //define function start.  

   {

       String stra = "do";   //define variable and assign value.

       String strb = method(stra);  //define variable and pass stra variable in method() function as a parameter.

       System.out.print(":"+stra + strb); //print value.  

   }

   String method(String stra)  //define function method  

   {  

       stra = stra + "good";   //add value

       System.out.print(stra);  //print value of stra

       return"good";  //return value

   }

}

Output:

dogood:dogood

6 0
3 years ago
Character literals are enclosed in ________; string literals are enclosed in ________. Group of answer choices double quotes; do
adelina 88 [10]

Answer:

Single quotes; Double quotes

Explanation:

Character literals is a type of literal in Java programming used for denoting constant valued character. Examples are 'g', '6', 'A' '+' etc.

String literals is a type of literal in Java programming used for representing or displaying of a sequence of characters or string values. Examples are "Hello Brainly user"

In Java programming, Character literals are enclosed in single quotes, string literals are enclosed in double quotes.

7 0
3 years ago
Write a function with two parameters, prefix (a string, using the string class from ) and levels (an unsigned integer). The func
Allisa [31]

Answer:

Here is the program:

#include <iostream>  //to use input output functions

#include <string>  // to use functions to manipulate strings

using namespace std;  //to identify objects cin cout

void function(string prefix, unsigned int levels){  // function that takes two parameters, a string, using the string class and levels an unsigned integer

   if (levels == 0) {  //if number of levels is equal to 0

       cout << prefix << endl;  //displays the value of prefix

       return;    }  

  for (int i = 1; i <=9 ; i++){  //iterates 1 through 9 times

       string sections = (levels == 1 ? "" : ".");  //if the number of levels is equal to 1 then empty space in sections variable otherwise stores a dot

       string output = prefix +  std::to_string(i) + sections;   // displays the string prefix followed by the section numbers. Here to_string is used to convert integer to string

       function(output, levels - 1);   } }   //calls function by passing the resultant string and levels-1  recursively to print the string prefix followed by section numbers

int main() {  // start of main function

   int level = 2;  //determines the number of levels

   function("BOX", level);  } //calls function by passing the string prefix and level value

Explanation:

The program has a function named function() that takes two parameters, prefix (a string, using the string class from ) and levels (an unsigned integer). The function prints the string prefix followed by "section numbers" of the form 1.1., 1.2., 1.3., and so on. The levels argument determines how many levels the section numbers have. If the value of levels is 0 means there is 0 level then the value of prefix is printed. The for loop iterates '1' through '9' times for number of digits in each level. If the number of levels is 1 then space is printed otherwise a dot is printed. The function() calls itself recursively to print the prefix string followed by section numbers.

Let us suppose that prefix = "BOX" and level = 1

If level = 1 then the loop for (int i = 1; i <=9 ; i++) works as follows:

At first iteration:

i = 1

i <=9 is true because value of i is 1

string sections = (levels == 1 ? "" : "."); this statement checks if the levels is equal to 1. It is true so empty space is stored in sections variable so,

sections = ""

Next, string output = prefix +  std::to_string(i) + sections; statement has prefix i.e BOX plus value of i which is 1 and this int value is converted to string by to_string() method plus sections has an empty space. So this statement becomes

string output = BOX + 1  

So this concatenates BOX with 1 hence output becomes:

output = BOX1

At second iteration:

i = 2

i <=9 is true because value of i is 2

string sections = (levels == 1 ? "" : "."); is true so

sections = ""

Next, string output = prefix +  std::to_string(i) + sections; statement becomes

string output = BOX + 2  

So this concatenates BOX with 1 hence output becomes:

output = BOX2

At third iteration:

i = 3

i <=9 is true because value of i is 3

string sections = (levels == 1 ? "" : "."); is true so

sections = ""

Next, string output = prefix +  std::to_string(i) + sections; statement becomes

string output = BOX + 3  

So this concatenates BOX with 1 hence output becomes:

output = BOX3

Now at each iteration the prefix string BOX is concatenated and printed along with the value of i. So at last iteration:

At last iteration:

i = 9

i ==9 is true because value of i is 9

string sections = (levels == 1 ? "" : "."); is true so

sections = ""

Next, string output = prefix +  std::to_string(i) + sections; statement becomes

string output = BOX + 9  

So this concatenates BOX with 1 hence output becomes:

output = BOX9

After this the loop breaks at i = 10 because the condition i<=9 becomes false. So the output of the entire program is:

BOX1                                                                                                                                          BOX2                                                                                                                                          BOX3                                                                                                                                          BOX4                                                                                                                                          BOX5                                                                                                                                          BOX6                                                                                                                                          BOX7                                                                                                                                          BOX8                                                                                                                                          BOX9  

The program along with the output is attached.

4 0
3 years ago
Full Form of CPU AND RAM ?
sweet [91]

Answer:

IN COMPUTER TERMS:

CPU is centrsl processing unit

RAM is random access memory

7 0
3 years ago
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The _______ displays the name of the open file and the program
jek_recluse [69]

Answer:

The Title Bar displays the name of the open file and the program.

8 0
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