Step Vi is something that is used to produces
The state of energy that is forbidden is 2p orbital. The correct option is b).
<h3>
What is the energy state of electrons?</h3>
The energy state of an electron depends upon the presence of the electron on the orbitals. Lower the energy they will be in the lower orbital. When they get higher energy they move to the higher orbital.
By using the Selection Rules for Electron Transitions
1.) ?l = +/- 1 and
2.) ?m = 0, +/- 1
The conservation of angular momentum is required by these laws. A photon's inherent angular momentum is 1. As 4p is higher than 2p and the electron is lowering its energy. So, it will go down to 2p orbital.
Thus, the correct option is b). 2p orbital.
The question is incomplete. Your full question is given below:
a) 3d
b) 2p
c) 1s
d) 2s
To learn more about the energy state of electrons, refer to the link:
brainly.com/question/4138621
#SPJ4
Solubility product constants are values to describe the saturation of ionic compounds with low solubility. A saturated solution is when there is a dynamic equilibrium between the solute dissolved, the dissociated ions, the undissolved and the compound. It is calculated from the product of the ion concentration in the solution. For barium chromate, the dissociation would be as follows:
BaCrO4 = Ba^2+ + (CrO4)^2-
So, the expression for the solubility product would be:
Ksp = [Ba^2+] [(CrO4)^2-]
we let x = [BaCrO4] = [Ba2+] = [(CrO4)2-] = 2.81x10^-3 g/L ( 1 mol / 253.35 g ) = 1.11x10^-5
Ksp = x(x)
Ksp= x^2
Ksp = (1.11x10^-5)^2
Ksp = 1.23x10^-10
The Ksp of Barium chromate at that same temperature for the solubility would be 1.23x10^-10.