The complete balanced chemical reactions are:
<span>HNO3 => CaCO3
+ 2HNO3 → Ca(NO3)2 + H2O + CO2(g)</span>
<span>H2SO4 => CaCO3
+ H2SO4 → CaSO4 + H2O + CO2(g) </span>
<span>So we see that 1 mole of CaCO3 is needed for 2 moles of HNO3 and similarly
to 1 mole of H2SO4.
</span>The number of moles can be calculated as the product of
volume and molarity, so:
moles H2SO4 = 1.7×10^−5 M * (15.5 x 10^9 L) = 263,500 mol
H2SO4
moles HNO3 = 8.9×10^−6 M * (15.5 x 10^9 L) = 137,950 mol
HNO3
So the total moles of CaCO3 required is:
moles CaCO3 = 263,500 mol * 1 + 137,950 mol * (1/2)
moles CaCO3 = 332,475 mol
The molar mass of CaCO3 is 100.086 g/mol, so the mass is:
mass CaCO3 = 332,475 mol * 100.086 g/mol
mass CaCO3 = 33,276,092.85 g = 33.3 x 10^3 kg
