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Vinil7 [7]
3 years ago
15

Arrange the following elements in order of decreasing electronegativity:

Chemistry
1 answer:
faltersainse [42]3 years ago
3 0

Answer:

Be,Mg,Ca,Sr,Ba.Ra[down the group electronegativity is decreasing]

Explanation:

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Chemistry question.
grandymaker [24]
Hello!

Percentage error = (true value - measured value)/true value x 100%

Percentage error = (27.7-27.0)/27.7 x100% = 25.3%
8 0
3 years ago
How many liters of a 6.0M solution Fe(SCN)2 are needed to prepare 2.0L of a 0.75M solution?
lubasha [3.4K]

Answer:

0.25L

Explanation:

Using the dilution formula

C1V1=C2V2

C1=6M

V1?

C2=0.75M

V2=2.0L

V1= C2V2/C1

V1=0.75*2.0/6

V1=0.25L

4 0
3 years ago
Read 2 more answers
If a student made a 2.5 solution using 1.5 moles of sucrose how many liters of water were used?
saul85 [17]

Answer:

1 mole.

Explanation:

Hello there!

2.5-1.5=1

Subtract the sucrose moles from the total moles, and there you are!

:)

3 0
3 years ago
Which statement describes the bonds in iron sulfate, FeSO4?
Feliz [49]

___

Regarding the bonds in FesO₄, Fe and S have an ionic bond, while S and O have covalent bonds.

Elements form bonds to increase their stability. The main types of bonds are:

  • Metallic bonds: they are formed between metals and the electrons are in a delocalized cloud.
  • Ionic bonds: they are formed between metals (lose electrons) and nonmetals (gain electrons)
  • Covalent bonds: they are formed between nonmetals, which share electrons.

Regarding the bonds in FesO₄:

  • Fe is a metal and S a nonmetal, thus they will form ionic bonds.
  • S and O are both nonmetals, thus they will form covalent bonds.

Regarding the bonds in FesO₄, Fe and S have an ionic bond, while S and O have covalent bonds.

Learn more: brainly.com/question/23882847

5 0
2 years ago
A sample of gas in a 14.6 L flexible container is at 25.0oC and 1.00atm. What is the volume of the sample when heated to 220.0oC
inn [45]

Answer: 24.1 L

Explanation:

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=14.6L\\T_1=25.0^oC=(25+273)K=298K\\V_2=?\\T_2=220.0^0C=(220+273)K=493K

Putting values in above equation, we get:

\frac{14.6}{298K}=\frac{V_2}{493}\\\\V_2=24.1L

Thus the volume of the sample when heated to 220.0oC and the pressure is constant is 24.1 L

7 0
3 years ago
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