Answer:
Step-by-step explanation:
In order to find the horizontal distance the ball travels, we need to know first how long it took to hit the ground. We will find that time in the y-dimension, and then use that time in the x-dimension, which is the dimension in question when we talk about horizontal distance. Here's what we know in the y-dimension:
a = -32 ft/s/s
v₀ = 0 (since the ball is being thrown straight out the window, the angle is 0 degrees, which translates to no upwards velocity at all)
Δx = -15 feet (negative because the ball lands 15 feet below the point from which it drops)
t = ?? sec.
The equation we will use is the one for displacement:
Δx =
and filling in:
which simplifies down to
so
so
t = .968 sec (That is not the correct number of sig fig's but if I use the correct number, the answer doesn't come out to be one of the choices given. So I deviate from the rules a bit here out of necessity.)
Now we use that time in the x-dimension. Here's what we know in that dimension specifically:
a = 0 (acceleration in this dimension is always 0)
v₀ = 80 ft/sec
t = .968 sec
Δx = ?? feet
We use the equation for displacement again, and filling in what we know in this dimension:
Δx =
and of course the portion of that after the plus sign goes to 0, leaving us with simply:
Δx = (80)(.968)
Δx = 77.46 feet
Convert gallons to ounces
There 128 ounces in 1 gallon
So you would multiply
(214gal)*(128oz/1gal)=27392 ounces
27392oz / 4 oz = 6848 cups
Divide 1017,36 by pi and by the height (the inverse of the formula for the volume):
1017,36/3,14 = 324
324/9 = 36
Answer:
Step-by-step explanation:
To obtain the standard form of the equation of the parabola y=2(x+4)^2-7, first perform the indicated operations:
y = 2[x^2 + 8x + 16 - 7], or
y = 2[x^2 + 8x + 9],
or y = 2x^2 + 16x + 18
None of the given possible answers match. The fourth one, D, is closest to the above result, differing only in the constant term (25 versus 18).