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stepan [7]
2 years ago
14

Given that DE is a midsegment for ABC and the length of DE is 8 units. What is the length of BC?

Mathematics
1 answer:
tresset_1 [31]2 years ago
4 0

Answer:

BC = 16 units

Step-by-step explanation:

Since DE is the midsegment of the triangle, based on the midsegment theorem, thus:

DE = ½(BC)

DE = 8 units

Plug in the value

8 = ½(BC)

Multiply both sides by 2

2*8 = BC

BC = 16 units

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Which linear function represents the line given by the point slope equation y + 7= 2/3(x+6)
Andrews [41]

Hello from MrBillDoesMath!

Answer:   f(x) =   (2/3)*x -3   -- which is not a provided answer..


Discussion:


We are given that y + 7 = (2/3) * (x + 6). Multiply out the right hand side:


y + 7 = (2/3) * x + (2/3) * 6 = (2/3) *x + 12/3

        =   (2/3)*x + 4


Subtract 7 from both sides:

y + 7 - 7 = (2/3)*x + 4 - 7

or

y =  (2/3)*x -3



Thank you,

MrB


y + 7= 2/3(x+6)

7 0
3 years ago
What are the coefficients in the expression 5x3 + 14x2 - 2x + 6?
Lostsunrise [7]

Answer: 5,14 and -2

Step-by-step explanation:

The coefficient  is the number next to the variable.

So this case the coefficients are 5,14 and -2

6 0
2 years ago
Read 2 more answers
J3herjjeodbehi4vdue duehduehd7ehee
Pie

The account already has $278

If you add and then subract 278 then the value will be the same

Your answer is B

Hopw this helps

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7 0
3 years ago
Read 2 more answers
If the weight (in grams) of cereal in a box of Lucky Charms is N(489,6), what is the probability that the box will contain less
Wittaler [7]

Answer:

0.000064 = 0.0064% probability that the box will contain less than the advertised weight of 466 g.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

N(489,6)

This means that \mu = 489, \sigma = 6

What is the probability that the box will contain less than the advertised weight of 466 g?

This is the p-value of Z when X = 466. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{466 - 489}{6}

Z = -3.83

Z = -3.83 has a p-value of 0.000064

0.000064 = 0.0064% probability that the box will contain less than the advertised weight of 466 g.

3 0
2 years ago
If a and b are two angles in standard position in Quadrant I, find cos(a-b) for the given function values. sin a=3/5and cos b=12
goldfiish [28.3K]

The identity in question is

cos(a - b) = cos(a) cos(b) + sin(a) sin(b)

so that

cos(a - b) = 12/37 cos(a) + 3/5 sin(b)

Since both a and b lie in the first quadrant, both cos(a) and sin(b) will be positive. Then it follows from the Pythagorean identity,

cos²(x) + sin²(x) = 1,

that

cos(a) = √(1 - sin²(a)) = 4/5

and

sin(b) = √(1 - cos²(b)) = 35/37

So,

cos(a - b) = 12/37 • 4/5 + 3/5 • 35/37 = 153/185

7 0
2 years ago
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